A community for students. Sign up today!
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Open

Nurali
 one year ago
Best ResponseYou've already chosen the best response.0If the output is to be set at 6.0 V, then across the other section (A), the voltage drop needed to be 3.0 V. At 0730, the resistance of the thermistor = 1.5 kΩ The current flowing through section (A): I=3V/1.5kΩ+1.5kΩ I=0.001 A Similarly, the same current flows through the section (B) 6.0 V =(Rv+1.5k)*(0.001A) Rv=4.5kΩ

Nurali
 one year ago
Best ResponseYou've already chosen the best response.0if correct please click best response.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.