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satellite73Best ResponseYou've already chosen the best response.3
pythatgoras \[a+bi=\sqrt{a^2+b^2}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
in your case \(a=7,b=1\) so you can just about do it in your head
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
\[\sqrt{7^2+1^2}=\sqrt{491}=\sqrt{50}=5\sqrt2\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
not much to memorize, the hypotenuse is the square root of the sum of the squares, as in a right triangle
 one year ago

JenniferSmart1Best ResponseYou've already chosen the best response.0
but what has an "i" to do with a triangle?
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
dw:1358396646228:dw
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
the complex numbers live in the complex plane the absolute value is the distance from the origin, which you get via pythagoras \[a^2+b^2=h^2\] \[h=\sqrt{a^2+b^2}\]
 one year ago

JenniferSmart1Best ResponseYou've already chosen the best response.0
is the triangle always in that quadrant?
 one year ago

CallistoBest ResponseYou've already chosen the best response.2
No, it depends on the complex number. Let a, b = +ve a+bi => quad. I a + bi => quad. II a  bi => quad. III a  bi => quad. IV
 one year ago

JenniferSmart1Best ResponseYou've already chosen the best response.0
ahh good to know...so is "a" and "b" the length of the lines?
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
it doesn't make any difference however, what quadrant you are in, it is still \[a+bi=\sqrt{a^2+b^2}\] i just put it there because your number was \(7i\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
dw:1358397280980:dw
 one year ago

CallistoBest ResponseYou've already chosen the best response.2
dw:1358397320522:dw
 one year ago

JenniferSmart1Best ResponseYou've already chosen the best response.0
That makes sense...I just have one more dumb question a+bi....is that the location of the point at the end of that line?
 one year ago

JenniferSmart1Best ResponseYou've already chosen the best response.0
oh no that is the length of the line....durrr..sorry!!!1
 one year ago

JenniferSmart1Best ResponseYou've already chosen the best response.0
the absolute value of a+bi is the length of the line...correct?
 one year ago

CallistoBest ResponseYou've already chosen the best response.2
a + bi a = number (coordinate) in the real part b = number (coordinate) in the imaginary part  a+bi  = length of the line => yes, I think (Actually... I haven't learnt it in the lesson yet.. So...)
 one year ago

JenniferSmart1Best ResponseYou've already chosen the best response.0
that's cool...It makes sense to me though. Thanks soo much @Callisto =)
 one year ago

satellite73Best ResponseYou've already chosen the best response.3
yes, it is the length of the line, that is, the distance between the complex number \(a+bi\) and the origin
 one year ago
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