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satellite73 Group TitleBest ResponseYou've already chosen the best response.2
first off you can reduce, just like with real numbers then multiply top and bottom by \(i\)
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.0
because i*i=1
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.0
or 1/i=i
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
Is our goal to get the imaginary number out of the denominator?
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
dw:1358398893659:dw
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
\[\frac{2}{8i}=\frac{1}{4i}=\frac{1}{4i}\times \frac{i}{i}=\frac{i}{4i^2}=\frac{i}{4}\]
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
What is wrong if I say 1/i=i
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
it is \(\frac{1}{i}=i\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
@sauravshakya you cannot use \(\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}\) unless \(a\) and \(b\) are real
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
ya I got how u got 1/i=i But dw:1358399037098:dw this doesn't work
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
no it does not
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
1 and 1 are real
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
even this doesn't work \[\sqrt{a}\sqrt{b}=\sqrt{ab}\] unless \(a\) and \(b\) are positive numbers
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
excuse me i said 'real' and i meant 'positive' my mistake
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.0
oh I got it...
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
@JenniferSmart1 yes the goal is to get the complex number out of the denominator to write in standard form \(a+bi\)
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
oh ok
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
make sense
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
so i*i=1?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
I'm too tired...I'll look at it again tomorrow. Thanks guys
 one year ago
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