JenniferSmart1
why is this true?
\[\frac{2}{8i}=\frac i 4\]



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anonymous
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first off you can reduce, just like with real numbers
then multiply top and bottom by \(i\)

matricked
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because i*i=1

matricked
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or 1/i=i

JenniferSmart1
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Is our goal to get the imaginary number out of the denominator?

sauravshakya
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dw:1358398893659:dw

anonymous
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\[\frac{2}{8i}=\frac{1}{4i}=\frac{1}{4i}\times \frac{i}{i}=\frac{i}{4i^2}=\frac{i}{4}\]

sauravshakya
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What is wrong if I say 1/i=i

anonymous
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it is \(\frac{1}{i}=i\)

anonymous
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@sauravshakya you cannot use \(\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}\) unless \(a\) and \(b\) are real

sauravshakya
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ya I got how u got 1/i=i
But dw:1358399037098:dw this doesn't work

anonymous
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no it does not

sauravshakya
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1 and 1 are real

anonymous
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even this doesn't work
\[\sqrt{a}\sqrt{b}=\sqrt{ab}\] unless \(a\) and \(b\) are positive numbers

anonymous
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excuse me i said 'real' and i meant 'positive' my mistake

sauravshakya
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oh I got it...

anonymous
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@JenniferSmart1 yes the goal is to get the complex number out of the denominator to write in standard form \(a+bi\)

JenniferSmart1
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oh ok

JenniferSmart1
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make sense

JenniferSmart1
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so i*i=1?

JenniferSmart1
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I'm too tired...I'll look at it again tomorrow. Thanks guys