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satellite73
 one year ago
Best ResponseYou've already chosen the best response.2first off you can reduce, just like with real numbers then multiply top and bottom by \(i\)

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0Is our goal to get the imaginary number out of the denominator?

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358398893659:dw

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{2}{8i}=\frac{1}{4i}=\frac{1}{4i}\times \frac{i}{i}=\frac{i}{4i^2}=\frac{i}{4}\]

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.0What is wrong if I say 1/i=i

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2it is \(\frac{1}{i}=i\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2@sauravshakya you cannot use \(\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}\) unless \(a\) and \(b\) are real

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.0ya I got how u got 1/i=i But dw:1358399037098:dw this doesn't work

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.01 and 1 are real

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2even this doesn't work \[\sqrt{a}\sqrt{b}=\sqrt{ab}\] unless \(a\) and \(b\) are positive numbers

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2excuse me i said 'real' and i meant 'positive' my mistake

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2@JenniferSmart1 yes the goal is to get the complex number out of the denominator to write in standard form \(a+bi\)

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0I'm too tired...I'll look at it again tomorrow. Thanks guys
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