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anonymous
 4 years ago
why is this true?
\[\frac{2}{8i}=\frac i 4\]
anonymous
 4 years ago
why is this true? \[\frac{2}{8i}=\frac i 4\]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first off you can reduce, just like with real numbers then multiply top and bottom by \(i\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is our goal to get the imaginary number out of the denominator?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1358398893659:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{2}{8i}=\frac{1}{4i}=\frac{1}{4i}\times \frac{i}{i}=\frac{i}{4i^2}=\frac{i}{4}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is wrong if I say 1/i=i

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is \(\frac{1}{i}=i\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya you cannot use \(\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}\) unless \(a\) and \(b\) are real

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya I got how u got 1/i=i But dw:1358399037098:dw this doesn't work

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0even this doesn't work \[\sqrt{a}\sqrt{b}=\sqrt{ab}\] unless \(a\) and \(b\) are positive numbers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0excuse me i said 'real' and i meant 'positive' my mistake

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@JenniferSmart1 yes the goal is to get the complex number out of the denominator to write in standard form \(a+bi\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm too tired...I'll look at it again tomorrow. Thanks guys
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