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Krishnadas Group TitleBest ResponseYou've already chosen the best response.0
where is the question????
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
dw:1358405158149:dw find force at '1'.(gravitational)
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
@Krishnadas
 one year ago

Krishnadas Group TitleBest ResponseYou've already chosen the best response.0
F=GM1M2/r^2....and use vector addition
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
plz solve it i hav forgotten
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
@krishnadas
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
can any one hlp me out with this question plz....:((((
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
hey plz reply that among u can anyone can solve it or not?
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
it's easy.dw:1358406095611:dw find out the three forces and then add them vectorially.
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
i'll calculate F4 for youdw:1358406459709:dw \[\begin{align} F_{4}&=\frac{Gm.m}{r^{2}}\\ &=\frac{Gm^{2}}{2a^{2}}\\&=\frac{K}{2}\end{align}\] using the same formula, find F3 and F2 you'll end up with K for both of them. taking the vectorial sum of f2 and f3, \[\Large\begin{align} F_{23}&=\sqrt{F_1^2+F_2^2}\\&=\sqrt{2}K\end{align}\] since F2 and F3 are equal in magnitude, F23 is at a 45 degree angle to either of those two forces. i.e.dw:1358407097861:dw now, since F4 and F23 are in the same direction, you can just add them up . therefore, \(\Large F_{total}=F_{23}+F_{4}\)
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
I'm so sorry. Huge mistake in the direction of forces.dw:1358407602553:dw
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
i'm nt getting u @rajathsbhat
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
which part?
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
dw:1358408936334:dw may i right
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
k/2?i hav nt understood
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
i have just used k to make things look clean \[\Large K=\frac{GM^{2}}{a^{2}}\]
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
F23 is the resultant force of F2 and F3.
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
f total=k/2+root 2k?
 one year ago

Ruchi. Group TitleBest ResponseYou've already chosen the best response.0
?\[\sqrt{2a}\]
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
no \(\sqrt{2}*a\)
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
the pythagoras theorem: that side=\(\sqrt{a^{2}+a^{2}}=\sqrt{2a^{2}}=\sqrt{2}a\)
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
no \[\large \frac{Gm^2}{2a^{2}}\]
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
the denominator is \((\sqrt{2}a)^{2}\)
 one year ago
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