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Krishnadas
 one year ago
Best ResponseYou've already chosen the best response.0where is the question????

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358405158149:dw find force at '1'.(gravitational)

Krishnadas
 one year ago
Best ResponseYou've already chosen the best response.0F=GM1M2/r^2....and use vector addition

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0plz solve it i hav forgotten

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0can any one hlp me out with this question plz....:((((

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0hey plz reply that among u can anyone can solve it or not?

rajathsbhat
 one year ago
Best ResponseYou've already chosen the best response.3it's easy.dw:1358406095611:dw find out the three forces and then add them vectorially.

rajathsbhat
 one year ago
Best ResponseYou've already chosen the best response.3i'll calculate F4 for youdw:1358406459709:dw \[\begin{align} F_{4}&=\frac{Gm.m}{r^{2}}\\ &=\frac{Gm^{2}}{2a^{2}}\\&=\frac{K}{2}\end{align}\] using the same formula, find F3 and F2 you'll end up with K for both of them. taking the vectorial sum of f2 and f3, \[\Large\begin{align} F_{23}&=\sqrt{F_1^2+F_2^2}\\&=\sqrt{2}K\end{align}\] since F2 and F3 are equal in magnitude, F23 is at a 45 degree angle to either of those two forces. i.e.dw:1358407097861:dw now, since F4 and F23 are in the same direction, you can just add them up . therefore, \(\Large F_{total}=F_{23}+F_{4}\)

rajathsbhat
 one year ago
Best ResponseYou've already chosen the best response.3I'm so sorry. Huge mistake in the direction of forces.dw:1358407602553:dw

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0i'm nt getting u @rajathsbhat

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358408936334:dw may i right

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0k/2?i hav nt understood

rajathsbhat
 one year ago
Best ResponseYou've already chosen the best response.3i have just used k to make things look clean \[\Large K=\frac{GM^{2}}{a^{2}}\]

rajathsbhat
 one year ago
Best ResponseYou've already chosen the best response.3F23 is the resultant force of F2 and F3.

rajathsbhat
 one year ago
Best ResponseYou've already chosen the best response.3the pythagoras theorem: that side=\(\sqrt{a^{2}+a^{2}}=\sqrt{2a^{2}}=\sqrt{2}a\)

rajathsbhat
 one year ago
Best ResponseYou've already chosen the best response.3no \[\large \frac{Gm^2}{2a^{2}}\]

rajathsbhat
 one year ago
Best ResponseYou've already chosen the best response.3the denominator is \((\sqrt{2}a)^{2}\)
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