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Ruchi.

  • 2 years ago

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  1. saisukruth
    • 2 years ago
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    answer

  2. Krishnadas
    • 2 years ago
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    where is the question????

  3. Ruchi.
    • 2 years ago
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    |dw:1358405158149:dw| find force at '1'.(gravitational)

  4. Ruchi.
    • 2 years ago
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    @Krishnadas

  5. Krishnadas
    • 2 years ago
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    F=GM1M2/r^2....and use vector addition

  6. Ruchi.
    • 2 years ago
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    plz solve it i hav forgotten

  7. Ruchi.
    • 2 years ago
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    @krishnadas

  8. Ruchi.
    • 2 years ago
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    can any one hlp me out with this question plz....:((((

  9. Ruchi.
    • 2 years ago
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    @hartnn

  10. Ruchi.
    • 2 years ago
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    hey plz reply that among u can anyone can solve it or not?

  11. rajathsbhat
    • 2 years ago
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    it's easy.|dw:1358406095611:dw| find out the three forces and then add them vectorially.

  12. rajathsbhat
    • 2 years ago
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    i'll calculate F4 for you|dw:1358406459709:dw| \[\begin{align} F_{4}&=\frac{Gm.m}{r^{2}}\\ &=\frac{Gm^{2}}{2a^{2}}\\&=\frac{K}{2}\end{align}\] using the same formula, find F3 and F2 you'll end up with K for both of them. taking the vectorial sum of f2 and f3, \[\Large\begin{align} F_{23}&=\sqrt{F_1^2+F_2^2}\\&=\sqrt{2}K\end{align}\] since F2 and F3 are equal in magnitude, F23 is at a 45 degree angle to either of those two forces. i.e.|dw:1358407097861:dw| now, since F4 and F23 are in the same direction, you can just add them up . therefore, \(\Large F_{total}=F_{23}+F_{4}\)

  13. rajathsbhat
    • 2 years ago
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    I'm so sorry. Huge mistake in the direction of forces.|dw:1358407602553:dw|

  14. Ruchi.
    • 2 years ago
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    i'm nt getting u @rajathsbhat

  15. rajathsbhat
    • 2 years ago
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    which part?

  16. Ruchi.
    • 2 years ago
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    |dw:1358408936334:dw| may i right

  17. Ruchi.
    • 2 years ago
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    k/2?i hav nt understood

  18. rajathsbhat
    • 2 years ago
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    i have just used k to make things look clean \[\Large K=\frac{GM^{2}}{a^{2}}\]

  19. Ruchi.
    • 2 years ago
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    f^23?

  20. rajathsbhat
    • 2 years ago
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    F23 is the resultant force of F2 and F3.

  21. Ruchi.
    • 2 years ago
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    f total=k/2+root 2k?

  22. rajathsbhat
    • 2 years ago
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    yup

  23. Ruchi.
    • 2 years ago
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    root 2a?

  24. rajathsbhat
    • 2 years ago
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    what?

  25. Ruchi.
    • 2 years ago
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    ?\[\sqrt{2a}\]

  26. rajathsbhat
    • 2 years ago
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    no \(\sqrt{2}*a\)

  27. Ruchi.
    • 2 years ago
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    y?

  28. rajathsbhat
    • 2 years ago
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    the pythagoras theorem: that side=\(\sqrt{a^{2}+a^{2}}=\sqrt{2a^{2}}=\sqrt{2}a\)

  29. Ruchi.
    • 2 years ago
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    gm^2/2a?

  30. rajathsbhat
    • 2 years ago
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    no \[\large \frac{Gm^2}{2a^{2}}\]

  31. rajathsbhat
    • 2 years ago
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    the denominator is \((\sqrt{2}a)^{2}\)

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