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Krishnadas
 2 years ago
Best ResponseYou've already chosen the best response.0where is the question????

Ruchi.
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1358405158149:dw find force at '1'.(gravitational)

Krishnadas
 2 years ago
Best ResponseYou've already chosen the best response.0F=GM1M2/r^2....and use vector addition

Ruchi.
 2 years ago
Best ResponseYou've already chosen the best response.0plz solve it i hav forgotten

Ruchi.
 2 years ago
Best ResponseYou've already chosen the best response.0can any one hlp me out with this question plz....:((((

Ruchi.
 2 years ago
Best ResponseYou've already chosen the best response.0hey plz reply that among u can anyone can solve it or not?

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.3it's easy.dw:1358406095611:dw find out the three forces and then add them vectorially.

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.3i'll calculate F4 for youdw:1358406459709:dw \[\begin{align} F_{4}&=\frac{Gm.m}{r^{2}}\\ &=\frac{Gm^{2}}{2a^{2}}\\&=\frac{K}{2}\end{align}\] using the same formula, find F3 and F2 you'll end up with K for both of them. taking the vectorial sum of f2 and f3, \[\Large\begin{align} F_{23}&=\sqrt{F_1^2+F_2^2}\\&=\sqrt{2}K\end{align}\] since F2 and F3 are equal in magnitude, F23 is at a 45 degree angle to either of those two forces. i.e.dw:1358407097861:dw now, since F4 and F23 are in the same direction, you can just add them up . therefore, \(\Large F_{total}=F_{23}+F_{4}\)

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.3I'm so sorry. Huge mistake in the direction of forces.dw:1358407602553:dw

Ruchi.
 2 years ago
Best ResponseYou've already chosen the best response.0i'm nt getting u @rajathsbhat

Ruchi.
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1358408936334:dw may i right

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.3i have just used k to make things look clean \[\Large K=\frac{GM^{2}}{a^{2}}\]

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.3F23 is the resultant force of F2 and F3.

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.3the pythagoras theorem: that side=\(\sqrt{a^{2}+a^{2}}=\sqrt{2a^{2}}=\sqrt{2}a\)

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.3no \[\large \frac{Gm^2}{2a^{2}}\]

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.3the denominator is \((\sqrt{2}a)^{2}\)
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