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AdeyNyx

  • 3 years ago

7. Write the equation y - 4 = -2(x - 5) in slope-intercept form.(Points : 1) y = -2x + 14 y = -2x + 5 y = -2x + 9 y = -2x + 6 8. If you are finding the line perpendicular to x + 3y = 5, what is the slope of the line?(Points : 1) -3/5 1/3 3 -3

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  1. anonymous
    • 3 years ago
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    it always works the same way 1) distributive law \[ y - 4 = -2(x - 5)\] \[y-4=-2x+10\] 2) solve for \(y\) \[y=-2x+14\]

  2. anonymous
    • 3 years ago
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    the slope of \(ax+by=c\) is \(-\frac{a}{b}\) in your case the slope of \[x+3y=5\] is \(-\frac{1}{3}\) perpendicular line has slope that is the negative reciprocal

  3. anonymous
    • 3 years ago
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    negative reciprocal of \(-\frac{1}{3}\) is \(3\)

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