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Simplify 2^3 * 4n^2 * 2^-n HELP PLS :D

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\[2^{3} \times 4n ^{2} \times 2^{-n}\]
\[2^{3} \times 2^{2}n ^{2} \times 2^{-n}\]

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Other answers:

pls help
pls help anyone? @AravindG
is that the qn ?
im still unsure of what to do?
would it be 16n?
no !
that is the simplified form
would that be final answer?
yep :)
answer in book is 2^ n-3?
but i am sure of my answer ! check the question again
2^3 times (2n)^2 times 2^ -n opps one difference
is there any difference?
can you pls work it out now lol?
i dont see any diff in question
anyways thanks
\[2^3 \times (2n)^2 \times 2^{-n}\]\[= 2^{3-n} \times 2^2n^2\]\[=2^{3-n+2}n^2\]\[=...\]

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