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Kuoministers

Simplify 2^3 * 4n^2 * 2^-n HELP PLS :D

  • one year ago
  • one year ago

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  1. Kuoministers
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    \[2^{3} \times 4n ^{2} \times 2^{-n}\]

    • one year ago
  2. Kuoministers
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    \[2^{3} \times 2^{2}n ^{2} \times 2^{-n}\]

    • one year ago
  3. Kuoministers
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    @Dido525

    • one year ago
  4. Kuoministers
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    @RolyPoly

    • one year ago
  5. Kuoministers
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    pls help

    • one year ago
  6. Kuoministers
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    help @exraven

    • one year ago
  7. Kuoministers
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    pls help anyone? @AravindG

    • one year ago
  8. AravindG
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    |dw:1358401518683:dw|

    • one year ago
  9. AravindG
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    is that the qn ?

    • one year ago
  10. Kuoministers
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    yes!!

    • one year ago
  11. AravindG
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    |dw:1358401570163:dw|

    • one year ago
  12. AravindG
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    |dw:1358401640822:dw|

    • one year ago
  13. Kuoministers
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    im still unsure of what to do?

    • one year ago
  14. AravindG
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    why??

    • one year ago
  15. Kuoministers
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    would it be 16n?

    • one year ago
  16. AravindG
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    no !

    • one year ago
  17. AravindG
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    |dw:1358401736501:dw|

    • one year ago
  18. Kuoministers
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    no?

    • one year ago
  19. AravindG
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    |dw:1358401756772:dw|

    • one year ago
  20. AravindG
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    |dw:1358401776612:dw|

    • one year ago
  21. AravindG
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    that is the simplified form

    • one year ago
  22. Kuoministers
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    would that be final answer?

    • one year ago
  23. AravindG
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    yep :)

    • one year ago
  24. Kuoministers
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    answer in book is 2^ n-3?

    • one year ago
  25. AravindG
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    but i am sure of my answer ! check the question again

    • one year ago
  26. Kuoministers
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    2^3 times (2n)^2 times 2^ -n opps one difference

    • one year ago
  27. AravindG
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    :O

    • one year ago
  28. Kuoministers
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    is there any difference?

    • one year ago
  29. Kuoministers
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    can you pls work it out now lol?

    • one year ago
  30. AravindG
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    i dont see any diff in question

    • one year ago
  31. Kuoministers
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    anyways thanks

    • one year ago
  32. RolyPoly
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    \[2^3 \times (2n)^2 \times 2^{-n}\]\[= 2^{3-n} \times 2^2n^2\]\[=2^{3-n+2}n^2\]\[=...\]

    • one year ago
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