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DLS
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\[\LARGE \lim_{x \rightarrow 0} \frac{1+e^{\frac{1}{x}}}{1e^{\frac{1}{x}}} \]

DLS
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1) 1
2)1
3)0
4)Does not exist

hartnn
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can u use L'Hopitals ?

DLS
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anything

hartnn
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then try, x= 1/y
to get y>infinity
and then L'Hopitals.

DLS
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dw:1358405846397:dw
how will we solve this LHL anyway?

hartnn
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where did 'a' come from ?
did you try x=1/y ?

DLS
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its 0 not a nevermind sry :o
and i dont want to use L hospital because i know answer is 4 :P

hartnn
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why do i get 1 ? :P

DLS
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LHL=1
RHL=1
Limit does not exist :o

hartnn
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confirmed with wolf ?

DLS
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no with answer key..:o
but how did we solve LHL to 1

hartnn
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hmm....you can put h=h in LHL to get same form as of RHL, that is of h>0+

DLS
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dw:1358406440539:dw
but this :/??

hartnn
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you found RHL ? or not ?
because above thing is just substituting x +h=a
for that i suggested, x=1/y instead.(and you get 1 then)

DLS
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why x=1/y?
can u show clearly :/

hartnn
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x=1/y
>1/x = y
to make the exponent of e as 'y'
so that using L'Hopitals is easy
(1+e^y)/(1e^y) > e^y/(e^y) >1

DLS
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itni si baat batane me aadha ghanta lagadia be :p

hartnn
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:P
but the limit doesn't exist, right ? you got that using LHL and RHL ?

DLS
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yes..

hartnn
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good :)