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DLS
 one year ago
Best ResponseYou've already chosen the best response.1\[\LARGE \lim_{x \rightarrow 0} \frac{1+e^{\frac{1}{x}}}{1e^{\frac{1}{x}}} \]

DLS
 one year ago
Best ResponseYou've already chosen the best response.11) 1 2)1 3)0 4)Does not exist

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2then try, x= 1/y to get y>infinity and then L'Hopitals.

DLS
 one year ago
Best ResponseYou've already chosen the best response.1dw:1358405846397:dw how will we solve this LHL anyway?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2where did 'a' come from ? did you try x=1/y ?

DLS
 one year ago
Best ResponseYou've already chosen the best response.1its 0 not a nevermind sry :o and i dont want to use L hospital because i know answer is 4 :P

DLS
 one year ago
Best ResponseYou've already chosen the best response.1LHL=1 RHL=1 Limit does not exist :o

DLS
 one year ago
Best ResponseYou've already chosen the best response.1no with answer key..:o but how did we solve LHL to 1

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2hmm....you can put h=h in LHL to get same form as of RHL, that is of h>0+

DLS
 one year ago
Best ResponseYou've already chosen the best response.1dw:1358406440539:dw but this :/??

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2you found RHL ? or not ? because above thing is just substituting x +h=a for that i suggested, x=1/y instead.(and you get 1 then)

DLS
 one year ago
Best ResponseYou've already chosen the best response.1why x=1/y? can u show clearly :/

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2x=1/y >1/x = y to make the exponent of e as 'y' so that using L'Hopitals is easy (1+e^y)/(1e^y) > e^y/(e^y) >1

DLS
 one year ago
Best ResponseYou've already chosen the best response.1itni si baat batane me aadha ghanta lagadia be :p

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2:P but the limit doesn't exist, right ? you got that using LHL and RHL ?
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