Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

DLS

  • one year ago

limits

  • This Question is Closed
  1. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\LARGE \lim_{x \rightarrow 0} \frac{1+e^{\frac{-1}{x}}}{1-e^{\frac{-1}{x}}} \]

  2. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    1) 1 2)-1 3)0 4)Does not exist

  3. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    can u use L'Hopitals ?

  4. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    anything

  5. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    then try, x= -1/y to get y->-infinity and then L'Hopitals.

  6. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1358405846397:dw| how will we solve this LHL anyway?

  7. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    where did 'a' come from ? did you try x=-1/y ?

  8. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    its 0 not a nevermind sry :o and i dont want to use L hospital because i know answer is 4 :P

  9. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    why do i get -1 ? :P

  10. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    LHL=-1 RHL=1 Limit does not exist :o

  11. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    confirmed with wolf ?

  12. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    no with answer key..:o but how did we solve LHL to -1

  13. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    hmm....you can put h=-h in LHL to get same form as of RHL, that is of h->0+

  14. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1358406440539:dw| but this :/??

  15. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you found RHL ? or not ? because above thing is just substituting x +h=a for that i suggested, x=-1/y instead.(and you get -1 then)

  16. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    why x=-1/y? can u show clearly :/

  17. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    x=-1/y ---->-1/x = y to make the exponent of e as 'y' so that using L'Hopitals is easy (1+e^y)/(1-e^y) -----> e^y/(-e^y) ---->-1

  18. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    itni si baat batane me aadha ghanta lagadia be :p

  19. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    :P but the limit doesn't exist, right ? you got that using LHL and RHL ?

  20. DLS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes..

  21. hartnn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    good :)

  22. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.