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## missylulu help on multivariable calc T-T... what are the relative extrema of f(x,y) = x^2 + e^y? is the answer none...? one year ago one year ago

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1. mukushla

clearly domain is $$\mathbb{R}^2$$ and for relative extrema we have$\frac{\partial f}{\partial x}=2x=0$$\frac{\partial f}{\partial y}=e^y=0$we should solve these equations simultaneously but u r right...answer is none because for all real values of y we have$e^y>0$