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clarkjets

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  • one year ago
  • one year ago

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  1. clarkjets
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    |dw:1358409590944:dw|

    • one year ago
  2. RolyPoly
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    \[\log_3(x+4)+\log_3(x-2)=3\]log a + log b = log (ab) \[\log_3(x+4)(x-2)=3\] (x+4)(x-2) = 3^3

    • one year ago
  3. clarkjets
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    so would it be x^2+2x-17=0 which makes the roots x = {3.243, -5.243}?

    • one year ago
  4. RolyPoly
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    Not quite, can you check again?

    • one year ago
  5. clarkjets
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    I'm sorry I can't seem to find where im going wrong

    • one year ago
  6. RolyPoly
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    The equation you got was wrong..

    • one year ago
  7. RolyPoly
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    (x+4)(x-2) = 3^3 x^2 + 2x - 8 - 3^3 =0 ^Simplify this

    • one year ago
  8. clarkjets
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    is it not x^2+2x-17 ?

    • one year ago
  9. RolyPoly
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    what is 3^3?

    • one year ago
  10. clarkjets
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    oh my apologies I was thing of multiplying, so it is x^2+2x+19?

    • one year ago
  11. RolyPoly
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    Hmmm... x^2 + 2x - 8 - 3^3 =0

    • one year ago
  12. clarkjets
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    x^2+2x-35=0 ?

    • one year ago
  13. RolyPoly
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    Yup :) Now, solve it~

    • one year ago
  14. clarkjets
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    x=5 and x=-7 ?

    • one year ago
  15. RolyPoly
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    Yes, but you have to reject one answer there.

    • one year ago
  16. RolyPoly
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    You cannot take log for a negative number.

    • one year ago
  17. clarkjets
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    -7 correct?

    • one year ago
  18. clarkjets
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    ok thank you so much

    • one year ago
  19. RolyPoly
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    You're welcome :)

    • one year ago
  20. RolyPoly
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    And yes, you need to reject -7 :)

    • one year ago
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