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anonymous
 3 years ago
Black body
any body painted completely with lamb black is 98% perfect black body... it appears black cause it absorbs almost all the light incident on it.. and doesn't reflect any .. then why is it that if i shine a laser on it.. i can easily see the spot???
anonymous
 3 years ago
Black body any body painted completely with lamb black is 98% perfect black body... it appears black cause it absorbs almost all the light incident on it.. and doesn't reflect any .. then why is it that if i shine a laser on it.. i can easily see the spot???

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0very good question! I too had the exact same question back when I was studying this. I would guess that it's because soot isn't a perfect absorber of light...but other that, i have no idea.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0even if it is NOT a perfect absorber.. it should absorb something right??.. i mean when white light is incident.. it absorbs almost all.. is it because.. the intensity of the laser is very high ( i mean its totally focused).. so it DOES absorb more than when incident on the other surface.. and its just that we can't make out?? but really i can't imagine.. even if we did have a PERFECT black body.. shinning a laser and not see a spot.. !!..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you know, i do think that it reflects only about 2 percent of the incident light. Because, imagine how intense the laser light would be if you pointed it directly at your eye!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but. you take the same laser light and shine on something else.. i really don't see any difference.. !!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I am doing it right now .. 5mWatt laser.. no difference :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0really? this calls for an experiment...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0on second thoughts.. maybe there is a difference :D.. looking closer i think i see that black indeed absorbs more

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0shine it into something more reflective... a mirror...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if i shine on mirror.. i ll spoil my eyes :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you have optical mouse. you can try with that!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i just tried it. You're right. You see more light than you'd expect. But I still think it's only 2% as intense as the initial light. If only there was a way to measure the intensity....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i used soot from camphor btw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or maybe soot isn't completely amorphous.....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@UnkleRhaukus @Carl_Pham @eashmore @vincentlyon.fr @CliffSedge

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0An ideal black body absorbs *and emits* perfectly. If you shine a laser on a spot, it should absorb all that light, then reemit it again, distributed isotropically and according to a nice Boltzmann distribution of frequencies. So, sure, you should see a spot. You can think of it as representing a small patch of the black body which you have momentarily heated to a significantly higher temperature, and which is therefore glowing. And this is before we even get into the fact that real black bodies have significant nonidealities... You may be confusing a black body with a perfect conductor of energy. You may be thinking that if you shine the laser on some small patch, the energy should be instantly conducted away until it spreads over the entire black body surface, and just raises the overall temperature of the body by some small fraction. But the quality of being a black body doesn't, so far as I know, necessarily encompass being a body that conducts energy without resistance, a sort of heat superconductor.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0interesting idea.. so what you are saying is.. the spot that i see on a normal body and the spot that i see on the black body may look the same but are totally different physical phenomena? on normal body its just reflection.. photons bouncing off (normal reflection i mean ,i ll use photon theory cause.. black body radiation :D ) but when it comes ot black body.. its absorbing, getting heat up .. and then starts reemitting .. which is in total contrast to normal reflection?.. wow interesting indeed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i mean't PERFECT black body!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but one problem with this theory.. if i shine blue laser.. to heat it up a lil bit.. then the spot should look RED.. cause to emit blue light.. it would require significantly high temperature.. and i don't think shining blue laser light is gonna heat it up any more than shinning red laser light.. so what you say??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what you gotta say raj?? did i find a flaw in the theory?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cause if what he says is right.. then .. if i kept on focusing the laser spot... the small patch keeps on heating even more and more and thus should give me different colors!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0infact now i believe that theory is completely flawed.. you can't expect the temperature of the black body to be high enough to start remitting.. for crying it out loud.. you saying.. shinning the laser is actually making it red hot??!!?.. ITS NOT RED HOT!!!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think Carl is right. But you have a point too..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no Carl is not right.. its absolutely wrong!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A perfect Black Body absorbs all light period. It radiates light when it is heated to glowing and the rate of emission is given by the Stefan Boltzmann Law and a spectrum given by Planck's blackbody radiation curve.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea i know that.. but that doesn't answer my question.. !!!!.. by pointing laser at it.. i m pretty sure it wouldn't be hot enough to start radiating..!!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Correct.. the point is the lamp black surface is not a perfect BB. The light you see is diffusely reflected. You think it is too much. What percentage you have to measured. The BB will radiate its spectrum as it is heated externally to a temperature where it glows. I'll bet you will see some significant reflection from any non laser light source if it is bright enough.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but the bb radiating thing doesn't come into the picture.. and yea even i believe the its just a diffused reflection and nothing more. but definitely it doesn't get heated up and start radiating!!!
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