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anonymous
 4 years ago
If set D is a subset of set E, then which of the following is true?
D ∩ E = D
D ∩ E = E
D ∩ E = Ø
would it be the first one D ∩ E = D?
anonymous
 4 years ago
If set D is a subset of set E, then which of the following is true? D ∩ E = D D ∩ E = E D ∩ E = Ø would it be the first one D ∩ E = D?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could you explain it? (my lesson didn't explain it well)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just google it the answer is most likely B

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i would've googled it anyways, but there are no good explanations.

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1do you know what a subset is ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait its A!!!! JUST GOOGLE IT RIGHT NOW LOL

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0reallyprettyboy, i don't think you understand. i want and explanation. :

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok i'll find one dont worry :)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1if A is the subset of B, then all elements of A are present in B ex : A={1,2} B={1,2,3,4} notice all elements of A are in B ok ?

chihiroasleaf
 4 years ago
Best ResponseYou've already chosen the best response.2dw:1358421673278:dw

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1so, if now you have to find the intersection (common elements) the it would be entire set A, right ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1similarly, since D is a subset, intersection is set D itself.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay:) so it is D ∩ E = D.

chihiroasleaf
 4 years ago
Best ResponseYou've already chosen the best response.2you're very welcome... :D
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