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 one year ago
please tell to how to solve question related to calclus and where &how to use integration &differentiation?
 one year ago
please tell to how to solve question related to calclus and where &how to use integration &differentiation?

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satellite73
 one year ago
Best ResponseYou've already chosen the best response.0rather a broad question, isn't it?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1Calculus Questions are easy to solve once you know the formulas :) integration is used in finding are of solids, figures, etc. differentiation can be used to find rate of change of a quantity. and both of these have many other applications.. if you have any specific question, you please ask :)

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0\[gm/l \int\limits_{l/2}^{+l/2}(rx)^2dx\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1you need to first expand (rx)^2 =.... ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\[(ab)^2=a^22ab+b^2 \\ (rx)^2 =... ?\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1thats correct, now \[\int x^n dx=x^{n+1}/(n+1) \\ \int x^2dx=... ?\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1it will be x^3/3 , as n+1 =3 \[ \int\limits_{l/2}^{+l/2}(x^22rx+r^2)dx\\= \int\limits_{l/2}^{+l/2}x^2dx2r\int\limits_{l/2}^{+l/2}x dx+r^2\int\limits_{l/2}^{+l/2}1dx = \\ =[x^3/3]_{l/2}^{+l/2} 2r [x^2/2]_{l/2}^{+l/2}+r^2[x]_{l/2}^{+l/2}\] got this ?

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0why u hav taken 2r &r out?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1because when we are integrating with respect to x, 'r' will be constant and can be taken out of integration and differentiation..

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0how u will know that x is a constant? or any digit or letter is a constant?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1do you see 'dx' in integration, ? means only 'x' is variable, all other letters are treated to be constant.

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0the letter attach to d like dx always only that letter r variable?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1sorry, yes. only that letter is variable. so here r is constant, x is variable.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1now l/2 is upper limit and l/2 is lower limit. \[[x^3/3]^{l/2}_{l/2}\] is solved by first putting x= upper limit  x= lower limit like this : (l/2)^3/3 (l/2)^3/3 got this first term ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1can you try for other 2 terms ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{l/2}^{+l/2}(x^22rx+r^2)dx\\= \int\limits_{l/2}^{+l/2}x^2dx2r\int\limits_{l/2}^{+l/2}x dx+r^2\int\limits_{l/2}^{+l/2}1dx = \\ =[x^3/3]_{l/2}^{+l/2} 2r [x^2/2]_{l/2}^{+l/2}+r^2[x]_{l/2}^{+l/2}= \\ = [(l/2)^3/(3)(l/2)^3/(3)]2r[(l/2)^2/(2)(l/2)^2/(2)]\\ +r^2[l/2(l/2)] \\ = 2*l^3/24 2r(2*l^2/8)+r^2(2l/2) \\ =l^3/12  rl^2/2+r^2l\]

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0hey this one is nt d answer.

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0plz can u provide me conversion chats

Ruchi.
 one year ago
Best ResponseYou've already chosen the best response.0example : how to convert kg into mass. like this can u provide me the chat in which about all unit conversion given.
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