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Rachel98
Group Title
Total lost on this question.
Question: Write a rule for the nth term of the sequence. Use your rule to find a100.–8, 9, 26, 43, 60, . . .
How far I've gotten (don't know if I'm even doing this right): Okay so I see that the difference in the sequence is an increase of 17. So the rule would be an =  25 + 17n . So now we can use this to find the 100th term. So now to find the 100th term we use the rule a*100 =  25 + 17*100 =
 one year ago
 one year ago
Rachel98 Group Title
Total lost on this question. Question: Write a rule for the nth term of the sequence. Use your rule to find a100.–8, 9, 26, 43, 60, . . . How far I've gotten (don't know if I'm even doing this right): Okay so I see that the difference in the sequence is an increase of 17. So the rule would be an =  25 + 17n . So now we can use this to find the 100th term. So now to find the 100th term we use the rule a*100 =  25 + 17*100 =
 one year ago
 one year ago

This Question is Closed

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
\[a_0 = 8\]\[ a_1 = 9\]Right? Does your rule work? \[a_n = 25 + 17n\]\[a_1 = 25 + 17(1) = 8\] Looks like you have an "off by one" error in there, unless the first term of the sequence is really 25, not 8 as the problem seems to state. You are on the right track!
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
Try solving the equation for a0. You've got the right difference, but the wrong starting condition.
 one year ago

Rachel98 Group TitleBest ResponseYou've already chosen the best response.0
Not really sure, do you mean a0 =  25 + 17(1) = 8? Then solve for a0?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
No, isn't a0 = 8?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
and if you are looking to find a0, n = 0
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
\[a_0 = 25 + 17(0) = 8?\] What do you have to do to make that formula work, if you can't change a0 or 0?
 one year ago

Rachel98 Group TitleBest ResponseYou've already chosen the best response.0
Um a0 =  25 + 17(0) =  8 = a0 =  25 =  8?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
Are we agreed that a1 = 9, a2 = 26, a3 = 43, a4 = 60?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
and that \[a_{n+1} = a_n + 17\]
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
So \[a_{0+1} = a_0 + 17\]but \[a_1 = 9\] so \[a_1 = 9 = a_0 + 17\]\[a_0 = 8\] \[a_1 = a_0 + 17\] \[a_2 = a_1 + 17 = (a_0 + 17)+ 17\] \[a_3 = a_2 + 17 = (a_1 + 17) + 17 = ((a_0 + 17) + 17) + 17\] \[a_n = a_0 + 17n\]
 one year ago

Rachel98 Group TitleBest ResponseYou've already chosen the best response.0
Okay, but how do you use the rule to find the hundreth term?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
n = 100 \[a_n = a_0 + 17(100)\]
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
You know what, you should look at your text and see if they like to start the sequence with n = 0 or n = 1. I did it with n = 0, but if the convention in your book is n = 1, you had the right formula already! n = 100 \[a_{100} = 25 + 17(100) = \] Sorry for the confusion!
 one year ago

Rachel98 Group TitleBest ResponseYou've already chosen the best response.0
Okay so a100 =  25 + 17*100 = a100 =  25 + 1700?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
Yes, I believe so.
 one year ago

Rachel98 Group TitleBest ResponseYou've already chosen the best response.0
Is there any other steps? Do we subtract 25 from 1700?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
That would make it look neater, yes, but the value is the same...
 one year ago

Rachel98 Group TitleBest ResponseYou've already chosen the best response.0
Okay, thanks for the help, it makes sense now.
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
Glad to hear I did no lasting harm!
 one year ago
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