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 one year ago
Total lost on this question.
Question: Write a rule for the nth term of the sequence. Use your rule to find a100.–8, 9, 26, 43, 60, . . .
How far I've gotten (don't know if I'm even doing this right): Okay so I see that the difference in the sequence is an increase of 17. So the rule would be an =  25 + 17n . So now we can use this to find the 100th term. So now to find the 100th term we use the rule a*100 =  25 + 17*100 =
 one year ago
Total lost on this question. Question: Write a rule for the nth term of the sequence. Use your rule to find a100.–8, 9, 26, 43, 60, . . . How far I've gotten (don't know if I'm even doing this right): Okay so I see that the difference in the sequence is an increase of 17. So the rule would be an =  25 + 17n . So now we can use this to find the 100th term. So now to find the 100th term we use the rule a*100 =  25 + 17*100 =

This Question is Closed

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1\[a_0 = 8\]\[ a_1 = 9\]Right? Does your rule work? \[a_n = 25 + 17n\]\[a_1 = 25 + 17(1) = 8\] Looks like you have an "off by one" error in there, unless the first term of the sequence is really 25, not 8 as the problem seems to state. You are on the right track!

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1Try solving the equation for a0. You've got the right difference, but the wrong starting condition.

Rachel98
 one year ago
Best ResponseYou've already chosen the best response.0Not really sure, do you mean a0 =  25 + 17(1) = 8? Then solve for a0?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1and if you are looking to find a0, n = 0

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1\[a_0 = 25 + 17(0) = 8?\] What do you have to do to make that formula work, if you can't change a0 or 0?

Rachel98
 one year ago
Best ResponseYou've already chosen the best response.0Um a0 =  25 + 17(0) =  8 = a0 =  25 =  8?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1Are we agreed that a1 = 9, a2 = 26, a3 = 43, a4 = 60?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1and that \[a_{n+1} = a_n + 17\]

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1So \[a_{0+1} = a_0 + 17\]but \[a_1 = 9\] so \[a_1 = 9 = a_0 + 17\]\[a_0 = 8\] \[a_1 = a_0 + 17\] \[a_2 = a_1 + 17 = (a_0 + 17)+ 17\] \[a_3 = a_2 + 17 = (a_1 + 17) + 17 = ((a_0 + 17) + 17) + 17\] \[a_n = a_0 + 17n\]

Rachel98
 one year ago
Best ResponseYou've already chosen the best response.0Okay, but how do you use the rule to find the hundreth term?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1n = 100 \[a_n = a_0 + 17(100)\]

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1You know what, you should look at your text and see if they like to start the sequence with n = 0 or n = 1. I did it with n = 0, but if the convention in your book is n = 1, you had the right formula already! n = 100 \[a_{100} = 25 + 17(100) = \] Sorry for the confusion!

Rachel98
 one year ago
Best ResponseYou've already chosen the best response.0Okay so a100 =  25 + 17*100 = a100 =  25 + 1700?

Rachel98
 one year ago
Best ResponseYou've already chosen the best response.0Is there any other steps? Do we subtract 25 from 1700?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1That would make it look neater, yes, but the value is the same...

Rachel98
 one year ago
Best ResponseYou've already chosen the best response.0Okay, thanks for the help, it makes sense now.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1Glad to hear I did no lasting harm!
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