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 2 years ago
Total lost on this question.
Question: Write a rule for the nth term of the sequence. Use your rule to find a100.–8, 9, 26, 43, 60, . . .
How far I've gotten (don't know if I'm even doing this right): Okay so I see that the difference in the sequence is an increase of 17. So the rule would be an =  25 + 17n . So now we can use this to find the 100th term. So now to find the 100th term we use the rule a*100 =  25 + 17*100 =
 2 years ago
Total lost on this question. Question: Write a rule for the nth term of the sequence. Use your rule to find a100.–8, 9, 26, 43, 60, . . . How far I've gotten (don't know if I'm even doing this right): Okay so I see that the difference in the sequence is an increase of 17. So the rule would be an =  25 + 17n . So now we can use this to find the 100th term. So now to find the 100th term we use the rule a*100 =  25 + 17*100 =

This Question is Closed

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1\[a_0 = 8\]\[ a_1 = 9\]Right? Does your rule work? \[a_n = 25 + 17n\]\[a_1 = 25 + 17(1) = 8\] Looks like you have an "off by one" error in there, unless the first term of the sequence is really 25, not 8 as the problem seems to state. You are on the right track!

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1Try solving the equation for a0. You've got the right difference, but the wrong starting condition.

Rachel98
 2 years ago
Best ResponseYou've already chosen the best response.0Not really sure, do you mean a0 =  25 + 17(1) = 8? Then solve for a0?

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1and if you are looking to find a0, n = 0

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1\[a_0 = 25 + 17(0) = 8?\] What do you have to do to make that formula work, if you can't change a0 or 0?

Rachel98
 2 years ago
Best ResponseYou've already chosen the best response.0Um a0 =  25 + 17(0) =  8 = a0 =  25 =  8?

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1Are we agreed that a1 = 9, a2 = 26, a3 = 43, a4 = 60?

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1and that \[a_{n+1} = a_n + 17\]

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1So \[a_{0+1} = a_0 + 17\]but \[a_1 = 9\] so \[a_1 = 9 = a_0 + 17\]\[a_0 = 8\] \[a_1 = a_0 + 17\] \[a_2 = a_1 + 17 = (a_0 + 17)+ 17\] \[a_3 = a_2 + 17 = (a_1 + 17) + 17 = ((a_0 + 17) + 17) + 17\] \[a_n = a_0 + 17n\]

Rachel98
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, but how do you use the rule to find the hundreth term?

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1n = 100 \[a_n = a_0 + 17(100)\]

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1You know what, you should look at your text and see if they like to start the sequence with n = 0 or n = 1. I did it with n = 0, but if the convention in your book is n = 1, you had the right formula already! n = 100 \[a_{100} = 25 + 17(100) = \] Sorry for the confusion!

Rachel98
 2 years ago
Best ResponseYou've already chosen the best response.0Okay so a100 =  25 + 17*100 = a100 =  25 + 1700?

Rachel98
 2 years ago
Best ResponseYou've already chosen the best response.0Is there any other steps? Do we subtract 25 from 1700?

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1That would make it look neater, yes, but the value is the same...

Rachel98
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, thanks for the help, it makes sense now.

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1Glad to hear I did no lasting harm!
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