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kirbykirby
Group Title
Find k such that f(x) is a probability density function (pdf):
 one year ago
 one year ago
kirbykirby Group Title
Find k such that f(x) is a probability density function (pdf):
 one year ago
 one year ago

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kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
\[f(x)=ke^{\frac{x\mu}{\theta}}\] for \[x>\mu\] Perhaps more legibly as: \[f(x)=k*\exp({\frac{x\mu}{\theta}})\]
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Usually there's a bound for x like 0<x<2, but here it's x>u, so do I integrate from u to infinity? (And set this integral equal to 1)
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
I don't need to know how to solve the integral (at least I don't think so yet). I'm just wondering what the bounds on the integral should be.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i think x> mu is just to tell that exponential term has negative exponent always, the bounds will be still infinity to infinity.
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Oh ok I think you are right :) When I think about it now... I wouldn't have found a numerical answer had I used mu as one of the bounds ._.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
because if x<mu, the integral might diverge.
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Oh right I see
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, even thats true,
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Ok well thank you :)!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 one year ago
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