kirbykirby Group Title Find k such that f(x) is a probability density function (pdf): one year ago one year ago

1. kirbykirby Group Title

$f(x)=ke^{-\frac{x-\mu}{\theta}}$ for $x>\mu$ Perhaps more legibly as: $f(x)=k*\exp({-\frac{x-\mu}{\theta}})$

2. kirbykirby Group Title

Usually there's a bound for x like 0<x<2, but here it's x>u, so do I integrate from u to infinity? (And set this integral equal to 1)

3. kirbykirby Group Title

I don't need to know how to solve the integral (at least I don't think so yet). I'm just wondering what the bounds on the integral should be.

4. hartnn Group Title

i think x> mu is just to tell that exponential term has negative exponent always, the bounds will be still -infinity to infinity.

5. kirbykirby Group Title

Oh ok I think you are right :) When I think about it now... I wouldn't have found a numerical answer had I used mu as one of the bounds ._.

6. hartnn Group Title

because if x<mu, the integral might diverge.

7. kirbykirby Group Title

Oh right I see

8. hartnn Group Title

yes, even thats true,

9. kirbykirby Group Title

Ok well thank you :)!

10. hartnn Group Title

welcome ^_^