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jazzygirl127
 one year ago
Best ResponseYou've already chosen the best response.09x2? are you working with polynomials or did you just type it wrong?

shashaboo
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358461205942:dw

slaaibak
 one year ago
Best ResponseYou've already chosen the best response.1there are no real solutions... x2 = 16/9 \[x = \pm {4 \over 3} i\]

jazzygirl127
 one year ago
Best ResponseYou've already chosen the best response.0this doesn't work because 34 doesn't equal 0 so there are no solutions

jazzygirl127
 one year ago
Best ResponseYou've already chosen the best response.0oops not 34 but it still doesn't work

slaaibak
 one year ago
Best ResponseYou've already chosen the best response.1she means: \[9x^2 + 16 = 0\]

shashaboo
 one year ago
Best ResponseYou've already chosen the best response.0@slaaibak how did u get that

jazzygirl127
 one year ago
Best ResponseYou've already chosen the best response.0oh ok thank you yes but it still doesn't work

slaaibak
 one year ago
Best ResponseYou've already chosen the best response.1\[9x^2 + 16 = 0 \rightarrow 9x^2 = 16\] \[x^2 = {16 \over 9}\] \[x = \pm \sqrt{16 \over9} \rightarrow x = \pm {4 \over 3} \times \sqrt{1} = \pm {4 \over 3}i\]

slaaibak
 one year ago
Best ResponseYou've already chosen the best response.1@jazzygirl127 yes, it does work.
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