anonymous
  • anonymous
what are the solutions? 9x2 + 16 = 0
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
9x2? are you working with polynomials or did you just type it wrong?
anonymous
  • anonymous
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slaaibak
  • slaaibak
there are no real solutions... x2 = -16/9 \[x = \pm {4 \over 3} i\]

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anonymous
  • anonymous
this doesn't work because 34 doesn't equal 0 so there are no solutions
anonymous
  • anonymous
oops not 34 but it still doesn't work
slaaibak
  • slaaibak
she means: \[9x^2 + 16 = 0\]
anonymous
  • anonymous
@slaaibak how did u get that
anonymous
  • anonymous
oh ok thank you yes but it still doesn't work
slaaibak
  • slaaibak
\[9x^2 + 16 = 0 \rightarrow 9x^2 = -16\] \[x^2 = {-16 \over 9}\] \[x = \pm \sqrt{-16 \over9} \rightarrow x = \pm {4 \over 3} \times \sqrt{-1} = \pm {4 \over 3}i\]
slaaibak
  • slaaibak
@jazzygirl127 yes, it does work.
anonymous
  • anonymous
thanks you (:
slaaibak
  • slaaibak
my pleasure

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