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jazzygirl127Best ResponseYou've already chosen the best response.0
9x2? are you working with polynomials or did you just type it wrong?
 one year ago

shashabooBest ResponseYou've already chosen the best response.0
dw:1358461205942:dw
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
there are no real solutions... x2 = 16/9 \[x = \pm {4 \over 3} i\]
 one year ago

jazzygirl127Best ResponseYou've already chosen the best response.0
this doesn't work because 34 doesn't equal 0 so there are no solutions
 one year ago

jazzygirl127Best ResponseYou've already chosen the best response.0
oops not 34 but it still doesn't work
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
she means: \[9x^2 + 16 = 0\]
 one year ago

shashabooBest ResponseYou've already chosen the best response.0
@slaaibak how did u get that
 one year ago

jazzygirl127Best ResponseYou've already chosen the best response.0
oh ok thank you yes but it still doesn't work
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
\[9x^2 + 16 = 0 \rightarrow 9x^2 = 16\] \[x^2 = {16 \over 9}\] \[x = \pm \sqrt{16 \over9} \rightarrow x = \pm {4 \over 3} \times \sqrt{1} = \pm {4 \over 3}i\]
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
@jazzygirl127 yes, it does work.
 one year ago
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