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## shashaboo 2 years ago what are the solutions? 9x2 + 16 = 0

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1. jazzygirl127

9x2? are you working with polynomials or did you just type it wrong?

2. shashaboo

|dw:1358461205942:dw|

3. slaaibak

there are no real solutions... x2 = -16/9 $x = \pm {4 \over 3} i$

4. jazzygirl127

this doesn't work because 34 doesn't equal 0 so there are no solutions

5. jazzygirl127

oops not 34 but it still doesn't work

6. slaaibak

she means: $9x^2 + 16 = 0$

7. shashaboo

@slaaibak how did u get that

8. jazzygirl127

oh ok thank you yes but it still doesn't work

9. slaaibak

$9x^2 + 16 = 0 \rightarrow 9x^2 = -16$ $x^2 = {-16 \over 9}$ $x = \pm \sqrt{-16 \over9} \rightarrow x = \pm {4 \over 3} \times \sqrt{-1} = \pm {4 \over 3}i$

10. slaaibak

@jazzygirl127 yes, it does work.

11. shashaboo

thanks you (:

12. slaaibak

my pleasure

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