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shashaboo

  • 3 years ago

what are the solutions? 9x2 + 16 = 0

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  1. jazzygirl127
    • 3 years ago
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    9x2? are you working with polynomials or did you just type it wrong?

  2. shashaboo
    • 3 years ago
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    |dw:1358461205942:dw|

  3. slaaibak
    • 3 years ago
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    there are no real solutions... x2 = -16/9 \[x = \pm {4 \over 3} i\]

  4. jazzygirl127
    • 3 years ago
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    this doesn't work because 34 doesn't equal 0 so there are no solutions

  5. jazzygirl127
    • 3 years ago
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    oops not 34 but it still doesn't work

  6. slaaibak
    • 3 years ago
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    she means: \[9x^2 + 16 = 0\]

  7. shashaboo
    • 3 years ago
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    @slaaibak how did u get that

  8. jazzygirl127
    • 3 years ago
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    oh ok thank you yes but it still doesn't work

  9. slaaibak
    • 3 years ago
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    \[9x^2 + 16 = 0 \rightarrow 9x^2 = -16\] \[x^2 = {-16 \over 9}\] \[x = \pm \sqrt{-16 \over9} \rightarrow x = \pm {4 \over 3} \times \sqrt{-1} = \pm {4 \over 3}i\]

  10. slaaibak
    • 3 years ago
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    @jazzygirl127 yes, it does work.

  11. shashaboo
    • 3 years ago
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    thanks you (:

  12. slaaibak
    • 3 years ago
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    my pleasure

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