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jazzygirl127
 2 years ago
Best ResponseYou've already chosen the best response.09x2? are you working with polynomials or did you just type it wrong?

shashaboo
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1358461205942:dw

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1there are no real solutions... x2 = 16/9 \[x = \pm {4 \over 3} i\]

jazzygirl127
 2 years ago
Best ResponseYou've already chosen the best response.0this doesn't work because 34 doesn't equal 0 so there are no solutions

jazzygirl127
 2 years ago
Best ResponseYou've already chosen the best response.0oops not 34 but it still doesn't work

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1she means: \[9x^2 + 16 = 0\]

shashaboo
 2 years ago
Best ResponseYou've already chosen the best response.0@slaaibak how did u get that

jazzygirl127
 2 years ago
Best ResponseYou've already chosen the best response.0oh ok thank you yes but it still doesn't work

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1\[9x^2 + 16 = 0 \rightarrow 9x^2 = 16\] \[x^2 = {16 \over 9}\] \[x = \pm \sqrt{16 \over9} \rightarrow x = \pm {4 \over 3} \times \sqrt{1} = \pm {4 \over 3}i\]

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1@jazzygirl127 yes, it does work.
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