anonymous
  • anonymous
Restriction for logs
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1358467325462:dw|
anonymous
  • anonymous
Now how do i find the restriction(s) for this ? :S
slaaibak
  • slaaibak
The thing in the bracket may not be less or equal to zero.

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anonymous
  • anonymous
x>-5, x>2 ?
slaaibak
  • slaaibak
yeah :)
anonymous
  • anonymous
it's only supposed to be x>2
anonymous
  • anonymous
i dont understand why
slaaibak
  • slaaibak
because the x has to satisfy both x>-5 and x>2, but since the has to be greater than 2, it can't fall between -5 and 2, because then the equation would be undefined
slaaibak
  • slaaibak
Think about it this way: The two restrictions must be met. Meaning, the number must be greater than 2 AND it must be greater than -5. But, if it is greater than 2, it is greater than -5! So, the greater than -5 is dominated by the greater than 2 restriction. Therefore the only restriction is greater than 2
anonymous
  • anonymous
Ohhhhh, helps !
anonymous
  • anonymous
but cant there be more than one restriction ? :S
slaaibak
  • slaaibak
There can. for instance, it it was log(-x + 7) + log(x+2), the restrictions would be -x + 7 > 0 AND x + 2 > 0 so, it's x< 7 AND x> -2 which reduces to: -2 < x < 7

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