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burhan101

  • 3 years ago

Restriction for logs

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  1. burhan101
    • 3 years ago
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    |dw:1358467325462:dw|

  2. burhan101
    • 3 years ago
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    Now how do i find the restriction(s) for this ? :S

  3. slaaibak
    • 3 years ago
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    The thing in the bracket may not be less or equal to zero.

  4. burhan101
    • 3 years ago
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    x>-5, x>2 ?

  5. slaaibak
    • 3 years ago
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    yeah :)

  6. burhan101
    • 3 years ago
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    it's only supposed to be x>2

  7. burhan101
    • 3 years ago
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    i dont understand why

  8. slaaibak
    • 3 years ago
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    because the x has to satisfy both x>-5 and x>2, but since the has to be greater than 2, it can't fall between -5 and 2, because then the equation would be undefined

  9. slaaibak
    • 3 years ago
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    Think about it this way: The two restrictions must be met. Meaning, the number must be greater than 2 AND it must be greater than -5. But, if it is greater than 2, it is greater than -5! So, the greater than -5 is dominated by the greater than 2 restriction. Therefore the only restriction is greater than 2

  10. burhan101
    • 3 years ago
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    Ohhhhh, helps !

  11. burhan101
    • 3 years ago
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    but cant there be more than one restriction ? :S

  12. slaaibak
    • 3 years ago
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    There can. for instance, it it was log(-x + 7) + log(x+2), the restrictions would be -x + 7 > 0 AND x + 2 > 0 so, it's x< 7 AND x> -2 which reduces to: -2 < x < 7

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