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burhan101
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358467325462:dw

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0Now how do i find the restriction(s) for this ? :S

slaaibak
 one year ago
Best ResponseYou've already chosen the best response.1The thing in the bracket may not be less or equal to zero.

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0it's only supposed to be x>2

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand why

slaaibak
 one year ago
Best ResponseYou've already chosen the best response.1because the x has to satisfy both x>5 and x>2, but since the has to be greater than 2, it can't fall between 5 and 2, because then the equation would be undefined

slaaibak
 one year ago
Best ResponseYou've already chosen the best response.1Think about it this way: The two restrictions must be met. Meaning, the number must be greater than 2 AND it must be greater than 5. But, if it is greater than 2, it is greater than 5! So, the greater than 5 is dominated by the greater than 2 restriction. Therefore the only restriction is greater than 2

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0but cant there be more than one restriction ? :S

slaaibak
 one year ago
Best ResponseYou've already chosen the best response.1There can. for instance, it it was log(x + 7) + log(x+2), the restrictions would be x + 7 > 0 AND x + 2 > 0 so, it's x< 7 AND x> 2 which reduces to: 2 < x < 7
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