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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1358467325462:dw
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
Now how do i find the restriction(s) for this ? :S
 one year ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
The thing in the bracket may not be less or equal to zero.
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
x>5, x>2 ?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
it's only supposed to be x>2
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
i dont understand why
 one year ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
because the x has to satisfy both x>5 and x>2, but since the has to be greater than 2, it can't fall between 5 and 2, because then the equation would be undefined
 one year ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
Think about it this way: The two restrictions must be met. Meaning, the number must be greater than 2 AND it must be greater than 5. But, if it is greater than 2, it is greater than 5! So, the greater than 5 is dominated by the greater than 2 restriction. Therefore the only restriction is greater than 2
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
Ohhhhh, helps !
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
but cant there be more than one restriction ? :S
 one year ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
There can. for instance, it it was log(x + 7) + log(x+2), the restrictions would be x + 7 > 0 AND x + 2 > 0 so, it's x< 7 AND x> 2 which reduces to: 2 < x < 7
 one year ago
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