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haterofmath
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Graph the function, not by plotting points, but by starting from the graphs in the figures below. State the domain, range, and asymptote.
y = 1 + log3 x
 one year ago
 one year ago
haterofmath Group Title
Graph the function, not by plotting points, but by starting from the graphs in the figures below. State the domain, range, and asymptote. y = 1 + log3 x
 one year ago
 one year ago

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wio Group TitleBest ResponseYou've already chosen the best response.1
Everyone is welcome on this site.
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
it is \(y=1+\log_3(x)\) ?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
you cannot take the log of a non  positive number, so domain is \[(0,\infty)\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
range of log is all real numbers, so range of \(1+\log_3(x)\) is also all real numbers \(\mathbb{R}\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
there is no horizontal asymptote, but there is a vertical asymptote at \(x=0\) as the function goes to \(\infty\) as \(x\to 0\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
here is a nice picture, make sure you click on "real valued plot" because wolfram will give you the complex log if you are not careful http://www.wolframalpha.com/input/?i=1%2Blog%28x%29
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
actually, here is one for \(y=1+\log_3(x)\) http://www.wolframalpha.com/input/?i=1%2Blog_3%28x%29
 one year ago
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