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JenniferSmart1
how do I get the vertex of a parabola? \[y=x^2+16x+64\]
You could put it in vertex form by completing the square of the right side
I don't think we need to complete the square... \[y=(x+8)^2\]
Yep thats it you noticed (16/2)^2 is 64 so you didnt have to do anything So the vertex is (-8,0)
how do you know that that is the vertex? What's the formula for finding a vertex?
Well when its in vertex form y=a(x-h)^2+k (h,k) is the vertex in this case h is -8 and k is 0
Makes sense! Thanks!!!