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JenniferSmart1

how do I get the vertex of a parabola? \[y=x^2+16x+64\]

  • one year ago
  • one year ago

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  1. CalebBeavers
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    You could put it in vertex form by completing the square of the right side

    • one year ago
  2. JenniferSmart1
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    I don't think we need to complete the square... \[y=(x+8)^2\]

    • one year ago
  3. CalebBeavers
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    Yep thats it you noticed (16/2)^2 is 64 so you didnt have to do anything So the vertex is (-8,0)

    • one year ago
  4. JenniferSmart1
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    how do you know that that is the vertex? What's the formula for finding a vertex?

    • one year ago
  5. CalebBeavers
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    Well when its in vertex form y=a(x-h)^2+k (h,k) is the vertex in this case h is -8 and k is 0

    • one year ago
  6. JenniferSmart1
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    Makes sense! Thanks!!!

    • one year ago
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