anonymous
  • anonymous
how do I get the vertex of a parabola? \[y=x^2+16x+64\]
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
You could put it in vertex form by completing the square of the right side
anonymous
  • anonymous
I don't think we need to complete the square... \[y=(x+8)^2\]
anonymous
  • anonymous
Yep thats it you noticed (16/2)^2 is 64 so you didnt have to do anything So the vertex is (-8,0)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
how do you know that that is the vertex? What's the formula for finding a vertex?
anonymous
  • anonymous
Well when its in vertex form y=a(x-h)^2+k (h,k) is the vertex in this case h is -8 and k is 0
anonymous
  • anonymous
Makes sense! Thanks!!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.