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UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358469689716:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0You have to work out weather path ABC or ADC is shorter. path ABC = AB + BC path ADC= AD + DC you can use Pythagorus's theorem to calculate AB and (DC)

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0yeah i know im getting sqrt(40) for A to B and 6 for B to C

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0B is the correct answer but i can't get the exact distance from A to B and then from B to C

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0@UnkleRhaukus you there?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0sorry i got distracted, you've got AB right and you've got BC right too

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0how would i put the answer in a website? i think thats what im doing wrong.

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 can you assist me here too please

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1you want the total distance right? do you know the shortest rout?

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0yes / B is the shortest

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1from A to B is \(\sqrt{2^2+6^2}=\sqrt{40}\) and from B to C is 6

mariomintchev
 one year ago
Best ResponseYou've already chosen the best response.0ok. how would i put that in on a hw website?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1so that distance total is\[6+\sqrt{40}\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1i have no idea maybe it wants a decimal

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{40}=\sqrt{4\times10}=\sqrt{2^2\times2\times5}=2\sqrt{2}\sqrt{5}\]
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