anonymous
  • anonymous
...never got help so im reposting
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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UnkleRhaukus
  • UnkleRhaukus
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UnkleRhaukus
  • UnkleRhaukus
You have to work out weather path ABC or ADC is shorter. path ABC = AB + BC path ADC= AD + DC you can use Pythagorus's theorem to calculate AB and (DC)

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anonymous
  • anonymous
yeah i know im getting sqrt(40) for A to B and 6 for B to C
anonymous
  • anonymous
B is the correct answer but i can't get the exact distance from A to B and then from B to C
anonymous
  • anonymous
@UnkleRhaukus you there?
UnkleRhaukus
  • UnkleRhaukus
sorry i got distracted, you've got AB right and you've got BC right too
anonymous
  • anonymous
how would i put the answer in a website? i think thats what im doing wrong.
anonymous
  • anonymous
@satellite73 can you assist me here too please
anonymous
  • anonymous
you want the total distance right? do you know the shortest rout?
anonymous
  • anonymous
yes / B is the shortest
anonymous
  • anonymous
from A to B is \(\sqrt{2^2+6^2}=\sqrt{40}\) and from B to C is 6
anonymous
  • anonymous
ok. how would i put that in on a hw website?
anonymous
  • anonymous
so that distance total is\[6+\sqrt{40}\]
anonymous
  • anonymous
i have no idea maybe it wants a decimal
anonymous
  • anonymous
https://www.wolframalpha.com/input/?i=6%2Bsqrt%2840%29
UnkleRhaukus
  • UnkleRhaukus
\[\sqrt{40}=\sqrt{4\times10}=\sqrt{2^2\times2\times5}=2\sqrt{2}\sqrt{5}\]

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