mariomintchev
...never got help so im reposting
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mariomintchev
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UnkleRhaukus
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|dw:1358469689716:dw|
UnkleRhaukus
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You have to work out weather path ABC or ADC is shorter.
path ABC = AB + BC
path ADC= AD + DC
you can use Pythagorus's theorem to calculate
AB and (DC)
mariomintchev
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yeah i know
im getting sqrt(40) for A to B
and
6 for B to C
mariomintchev
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B is the correct answer but i can't get the exact distance from A to B and then from B to C
mariomintchev
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@UnkleRhaukus you there?
UnkleRhaukus
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sorry i got distracted,
you've got AB right and
you've got BC right too
mariomintchev
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how would i put the answer in a website? i think thats what im doing wrong.
mariomintchev
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@satellite73 can you assist me here too please
anonymous
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you want the total distance right? do you know the shortest rout?
mariomintchev
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yes / B is the shortest
anonymous
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from A to B is \(\sqrt{2^2+6^2}=\sqrt{40}\) and from B to C is 6
mariomintchev
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ok. how would i put that in on a hw website?
anonymous
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so that distance total is\[6+\sqrt{40}\]
anonymous
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i have no idea
maybe it wants a decimal
UnkleRhaukus
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\[\sqrt{40}=\sqrt{4\times10}=\sqrt{2^2\times2\times5}=2\sqrt{2}\sqrt{5}\]