## mariomintchev Group Title ...never got help so im reposting one year ago one year ago

1. mariomintchev Group Title

2. UnkleRhaukus Group Title

|dw:1358469689716:dw|

3. UnkleRhaukus Group Title

You have to work out weather path ABC or ADC is shorter. path ABC = AB + BC path ADC= AD + DC you can use Pythagorus's theorem to calculate AB and (DC)

4. mariomintchev Group Title

yeah i know im getting sqrt(40) for A to B and 6 for B to C

5. mariomintchev Group Title

B is the correct answer but i can't get the exact distance from A to B and then from B to C

6. mariomintchev Group Title

@UnkleRhaukus you there?

7. UnkleRhaukus Group Title

sorry i got distracted, you've got AB right and you've got BC right too

8. mariomintchev Group Title

how would i put the answer in a website? i think thats what im doing wrong.

9. mariomintchev Group Title

@satellite73 can you assist me here too please

10. satellite73 Group Title

you want the total distance right? do you know the shortest rout?

11. mariomintchev Group Title

yes / B is the shortest

12. satellite73 Group Title

from A to B is $$\sqrt{2^2+6^2}=\sqrt{40}$$ and from B to C is 6

13. mariomintchev Group Title

ok. how would i put that in on a hw website?

14. satellite73 Group Title

so that distance total is$6+\sqrt{40}$

15. satellite73 Group Title

i have no idea maybe it wants a decimal

16. satellite73 Group Title
17. UnkleRhaukus Group Title

$\sqrt{40}=\sqrt{4\times10}=\sqrt{2^2\times2\times5}=2\sqrt{2}\sqrt{5}$