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## mariomintchev 2 years ago ...never got help so im reposting

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1. mariomintchev

2. UnkleRhaukus

|dw:1358469689716:dw|

3. UnkleRhaukus

You have to work out weather path ABC or ADC is shorter. path ABC = AB + BC path ADC= AD + DC you can use Pythagorus's theorem to calculate AB and (DC)

4. mariomintchev

yeah i know im getting sqrt(40) for A to B and 6 for B to C

5. mariomintchev

B is the correct answer but i can't get the exact distance from A to B and then from B to C

6. mariomintchev

@UnkleRhaukus you there?

7. UnkleRhaukus

sorry i got distracted, you've got AB right and you've got BC right too

8. mariomintchev

how would i put the answer in a website? i think thats what im doing wrong.

9. mariomintchev

@satellite73 can you assist me here too please

10. satellite73

you want the total distance right? do you know the shortest rout?

11. mariomintchev

yes / B is the shortest

12. satellite73

from A to B is $$\sqrt{2^2+6^2}=\sqrt{40}$$ and from B to C is 6

13. mariomintchev

ok. how would i put that in on a hw website?

14. satellite73

so that distance total is$6+\sqrt{40}$

15. satellite73

i have no idea maybe it wants a decimal

16. satellite73
17. UnkleRhaukus

$\sqrt{40}=\sqrt{4\times10}=\sqrt{2^2\times2\times5}=2\sqrt{2}\sqrt{5}$

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