rebecca1233
in a 40 ^0  45^0  90^0 right triangle, the hyptoenuse is 5m. how long are the legs?
please help



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rebecca1233
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oops first one is 45^0 too

rebecca1233
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so 45^0  45^0  90^0

jim_thompson5910
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Hint:
dw:1358468818520:dw

baziham
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dw:1358468848265:dw

rebecca1233
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so what do i do? can u help me get the answer?

jim_thompson5910
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The figure allows us to say
\[\Large x\sqrt{2} = 5\]

jim_thompson5910
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solve for x to get your answer

rebecca1233
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so i just 2 *5?


jim_thompson5910
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You have to divide both sides by \(\Large \sqrt{2}\), then rationalize the denominator (if the book requires you to do it)

rebecca1233
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so 5 divide by 2?

jim_thompson5910
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square root of 2

rebecca1233
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so 3

jim_thompson5910
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no, it's not 3

rebecca1233
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idk i suck at square rooting stuff

jim_thompson5910
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It's just simply \[\Large x = \frac{5}{\sqrt{2}}\]
optionally you can rationalize the denominator to get \[\Large x = \frac{5\sqrt{2}}{2}\]

rebecca1233
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5 divide square root 2 ?


rebecca1233
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1.41

rebecca1233
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1.414

jim_thompson5910
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that's the approximate value of the square root of 2

rebecca1233
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ok then what cause i gotta find how long the leg is

jim_thompson5910
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type this into your calculator
5/sqrt(2)

rebecca1233
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i did thats wat i got

jim_thompson5910
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you couldn't have gotten 1.414 if you typed in 5/sqrt(2)

rebecca1233
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well i did .

rebecca1233
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i got more numbers than that but i just didnt write em all

rebecca1233
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those were beginning numbers

jim_thompson5910
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i think you just typed in sqrt(2)

rebecca1233
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no.. i did the 5 / sqt 2

jim_thompson5910
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well it should be 3.5355339059

rebecca1233
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hmm..

jim_thompson5910
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my thoughts exactly, not sure how you got 1.414

rebecca1233
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hmm.. so what do i do now ?

jim_thompson5910
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once you have 3.5355339059, you are done finding the approximate leg length

rebecca1233
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okay. i got it.. thanks :)
