in a 40 ^0 - 45^0 - 90^0 right triangle, the hyptoenuse is 5m. how long are the legs? please help

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in a 40 ^0 - 45^0 - 90^0 right triangle, the hyptoenuse is 5m. how long are the legs? please help

Mathematics
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oops first one is 45^0 too
so 45^0 - 45^0 - 90^0
Hint: |dw:1358468818520:dw|

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|dw:1358468848265:dw|
so what do i do? can u help me get the answer?
The figure allows us to say \[\Large x\sqrt{2} = 5\]
solve for x to get your answer
so i just 2 *5?
no
You have to divide both sides by \(\Large \sqrt{2}\), then rationalize the denominator (if the book requires you to do it)
so 5 divide by 2?
square root of 2
so 3
no, it's not 3
idk i suck at square rooting stuff
It's just simply \[\Large x = \frac{5}{\sqrt{2}}\] optionally you can rationalize the denominator to get \[\Large x = \frac{5\sqrt{2}}{2}\]
5 divide square root 2 ?
yep
1.41
1.414
that's the approximate value of the square root of 2
ok then what cause i gotta find how long the leg is
type this into your calculator 5/sqrt(2)
i did thats wat i got
you couldn't have gotten 1.414 if you typed in 5/sqrt(2)
well i did .
i got more numbers than that but i just didnt write em all
those were beginning numbers
i think you just typed in sqrt(2)
no.. i did the 5 / sqt 2
well it should be 3.5355339059
hmm..
my thoughts exactly, not sure how you got 1.414
hmm.. so what do i do now ?
once you have 3.5355339059, you are done finding the approximate leg length
okay. i got it.. thanks :)
yw

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