anonymous
  • anonymous
in a 40 ^0 - 45^0 - 90^0 right triangle, the hyptoenuse is 5m. how long are the legs? please help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
oops first one is 45^0 too
anonymous
  • anonymous
so 45^0 - 45^0 - 90^0
jim_thompson5910
  • jim_thompson5910
Hint: |dw:1358468818520:dw|

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anonymous
  • anonymous
|dw:1358468848265:dw|
anonymous
  • anonymous
so what do i do? can u help me get the answer?
jim_thompson5910
  • jim_thompson5910
The figure allows us to say \[\Large x\sqrt{2} = 5\]
jim_thompson5910
  • jim_thompson5910
solve for x to get your answer
anonymous
  • anonymous
so i just 2 *5?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
You have to divide both sides by \(\Large \sqrt{2}\), then rationalize the denominator (if the book requires you to do it)
anonymous
  • anonymous
so 5 divide by 2?
jim_thompson5910
  • jim_thompson5910
square root of 2
anonymous
  • anonymous
so 3
jim_thompson5910
  • jim_thompson5910
no, it's not 3
anonymous
  • anonymous
idk i suck at square rooting stuff
jim_thompson5910
  • jim_thompson5910
It's just simply \[\Large x = \frac{5}{\sqrt{2}}\] optionally you can rationalize the denominator to get \[\Large x = \frac{5\sqrt{2}}{2}\]
anonymous
  • anonymous
5 divide square root 2 ?
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
1.41
anonymous
  • anonymous
1.414
jim_thompson5910
  • jim_thompson5910
that's the approximate value of the square root of 2
anonymous
  • anonymous
ok then what cause i gotta find how long the leg is
jim_thompson5910
  • jim_thompson5910
type this into your calculator 5/sqrt(2)
anonymous
  • anonymous
i did thats wat i got
jim_thompson5910
  • jim_thompson5910
you couldn't have gotten 1.414 if you typed in 5/sqrt(2)
anonymous
  • anonymous
well i did .
anonymous
  • anonymous
i got more numbers than that but i just didnt write em all
anonymous
  • anonymous
those were beginning numbers
jim_thompson5910
  • jim_thompson5910
i think you just typed in sqrt(2)
anonymous
  • anonymous
no.. i did the 5 / sqt 2
jim_thompson5910
  • jim_thompson5910
well it should be 3.5355339059
anonymous
  • anonymous
hmm..
jim_thompson5910
  • jim_thompson5910
my thoughts exactly, not sure how you got 1.414
anonymous
  • anonymous
hmm.. so what do i do now ?
jim_thompson5910
  • jim_thompson5910
once you have 3.5355339059, you are done finding the approximate leg length
anonymous
  • anonymous
okay. i got it.. thanks :)
jim_thompson5910
  • jim_thompson5910
yw

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