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burhan101

  • 3 years ago

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  1. SamuelAlden917
    • 3 years ago
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    K?

  2. burhan101
    • 3 years ago
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    |dw:1358469633397:dw|

  3. zepdrix
    • 3 years ago
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    \[\large 5^{2x}-6(5^x)+5=0 \qquad \rightarrow \qquad (5^x)^2-6(5^x)+5=0\] Make a substitution, Let \(\large u=5^x\). It should be fairly easy to factor from there :)

  4. burhan101
    • 3 years ago
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    ohhhhh ! thankyou :D

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