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misswiss123

  • 3 years ago

Factor the expression: x3 + 2x2 - 3x - 6

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  1. misswiss123
    • 3 years ago
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    Please help

  2. SamuelAlden917
    • 3 years ago
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    x^3 + 2x^2 - 3x - 6 x^2(x + 2) - 3(x + 2) (x^2 - 3)(x + 2) (x^2 - 3)(x + 2) or (x + √3)(x - √3)(x + 2)

  3. jim_thompson5910
    • 3 years ago
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    \[\Large x^3 + 2x^2 - 3x - 6\] \[\Large (x^3 + 2x^2) + (-3x - 6)\] \[\Large x^2(x + 2) -3(x + 2)\] \[\Large (x^2-3)(x + 2)\]

  4. misswiss123
    • 3 years ago
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    So what would I put down as the answer?

  5. Reaper534
    • 3 years ago
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    jim is right

  6. jim_thompson5910
    • 3 years ago
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    I would stop at \[\Large (x^2-3)(x + 2)\] instead of keep going to get \[\Large (x-\sqrt{3})(x+\sqrt{3})(x + 2)\] because most books I've seen factor over the rationals

  7. misswiss123
    • 3 years ago
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    Thank ya'll :)

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