## Sarah_Miller720 Group Title A baker has a bag of flour that is 11% whole wheat and a bag of flour that is 63% whole wheat. How many cups of each type does the baker need to make 12 cups of a flour mixture that is 50% whole wheat? (1 point) 3 cups of the 11% flour and 9 cups of the 63% flour 9 cups of the 11% flour and 3 cups of the 63% flour 3 cups of the 11% flour and 3 cups of the 63% flour 9 cups of the 11% flour and 9 cups of the 63% flour one year ago one year ago

1. mathstudent55

Let x = amount of 11% flour Let y = amount of 63% flour The amount of whole wheat in x cups of 11% flour is 11% of x or 0.11x The amount of whole wheat in y cups of 63% flour is 63% of y or 0.63y In the final result, 12 cups of 50% whole wheat have 50% of 12 cups or 0.5(12) = 6 cups The first equation is 0.11x + 0.63y = 6 The amount of flour used is x + y, and the result is 12, so the second equation is x + y = 12 Solve the system: 0.11x + 0.63y = 6 x + y = 12

2. Sarah_Miller720

so would my answer be 3 cups of the 11% flour and 9 cups of the 63% flour?

3. Sarah_Miller720

@mathstudent55

4. RyanL.

yeah you are right

5. Sarah_Miller720

Awesome thanks :)