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## anonymous 3 years ago PLEASE HELP .. On January 1 2010, Chessville has a population growth. Its population increases 7% each year. On the same day checkersville has a population of 70,000 people. Cheakersveille starts to expeirence a population decline . It's population decreases 4% each year . During what year will the population of Chessville first exceed that of Checkersville?

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1. anonymous

we are missing the initial population of "chessville"

2. anonymous

oh sorry its 50000

3. anonymous

$50000(1.07)^t=70,000(.96)^t$ solve for $$t$$

4. anonymous

lets see, divide by $$50,000$$ get $(1.07)^t=1.4(.96)^t$ divide by $$(.96)^t$$ get $\left(\frac{1.07}{.96}\right)^t=1.4$

5. anonymous

then use "change of base" formula to find $$t$$ $t=\frac{\ln(1.4)}{\ln(\frac{1.07}{.96})}$

6. anonymous

and of course a calculator

7. anonymous

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