monroe17
integral of (dx)/(49x)
I got (1/9)*log(49x)+C
But, my homework program keeps saying it's wrong... someone help?



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anonymous
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your homework program is mistaken
stick to your answer

anonymous
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maybe it is a syntax problem
maybe i wants \(\ln(49x)\) rather than \(\log(49x)\)

monroe17
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I tried that..
It says evaluate the indefinite integral
integral (dx)/(49x)

zepdrix
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Maybe it wants the Natural bars   for the contents of the log.

monroe17
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the what bars?..

anonymous
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@zepdrix good suggestion

anonymous
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\[\frac{1}{9}\log(49x)+C\] try

monroe17
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RIGHT! :) THANK YOU

zepdrix
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Oh cool :) yay team!