Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
jazzie
Group Title
Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160° respectively. Find the direction and magnitude of these forces. Round to two decimal places in all intermediate steps and in your final answer.
 one year ago
 one year ago
jazzie Group Title
Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160° respectively. Find the direction and magnitude of these forces. Round to two decimal places in all intermediate steps and in your final answer.
 one year ago
 one year ago

This Question is Open

ScienceGuy Group TitleBest ResponseYou've already chosen the best response.4
To determine the magnitude and direction of the forces, you must first resolve each into its horizontal and vertical vector components by using the cosine and sine functions. For the first vector, its horizontal component can be found via 100 lb cos 50 deg. (Make sure calculator is in degree mode). This yields 64.3 lbs in the positive x direction. For the vertical component we have 100 lb sin 50 deg which yields 76.6 lbs in the positive y direction. For the 2nd vector's components we need to be mindful that 160 degrees is the same as 20 degrees above the negative x axis. Thus any xvalues we obtain should be negative and our yvalue will be positive. Using the same idea as before, 50 lb cos 160 deg yields 47.0 lbs in the negative x direction. To determine the yvalue component, 50 lb sin 160 results in 17.1 lbs in the positive y direction. Having resolved both vectors into components we now add up the horizontal and vertical components respectively to find a single component in each x and y direction. Starting with the x components: 64.3 lbs + (47.0) lbs =17.3 lbs in the positive x direction Now the y components: 76.6 lbs + 17.1 lbs = 93.7 lbs in the positive y direction Now, we use pythagorean theorem to determine the magnitude (resultant) of these vectors and then use the tangent function to determine the angle. dw:1358477633869:dw (should be 17.3 not 17.1) \[R = \sqrt{93.7^{2}+17.3^{2}} = 95.3 lb\] To determine the angle/direction:\[\Theta =\tan^{1} (\frac{ 93.7 }{ 17.3 }) = 79.5^{o}\] Thus, your resulting vector will be 95.3 lb @ 79.5 degrees above the positive xaxis. This is a valid answer and need not be converted into Newtons (N) as a pound is the English unit of measure of force. Good Luck!
 one year ago

jazzie Group TitleBest ResponseYou've already chosen the best response.0
That makes so much more sense. Thank you !!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.