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Shido88

  • 2 years ago

Determine the value of f(-6), f(3/2), f(2c) and f(c+1), then simplify as much as possible Question : f(x) = 3x^2 - 4x

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  1. Shido88
    • 2 years ago
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    @Aylin help please :D

  2. Aylin
    • 2 years ago
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    Well, in the first two, just take the appropriate number and plug it in where x is. Then simplify it down. For the third one (2c) replace x with 2c, then see what you get. Same for the fourth one. The first two are plug'n'chug, but if you need help with the second two I'll stick around.

  3. Shido88
    • 2 years ago
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    the second two, just plug it in to every x in the problem ?

  4. Aylin
    • 2 years ago
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    Mhm. So f(2c) would like\[f(2c)=3 \times (2c)^{2}-4 \times (2c)\]

  5. Shido88
    • 2 years ago
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    Ok let me try thanks!

  6. Shido88
    • 2 years ago
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    ummm question

  7. Aylin
    • 2 years ago
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    Yes?

  8. Shido88
    • 2 years ago
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    kinda dumb question but for the first one f(-6) i did -6=3(-6)^2-4(-6) -6=108+24 -6=132 then at this step do you add the 6 over or minus the 132 over ?? lol

  9. Shido88
    • 2 years ago
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    it usually easier if one size has a (x)

  10. Aylin
    • 2 years ago
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    Well, the left side is f(-6) not -6. So when you get to f(-6)=132, you are finished with that part.

  11. Aylin
    • 2 years ago
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    Since you've found the value in the range (132) that corresponds to the value of -6 in the domain.

  12. Shido88
    • 2 years ago
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    i see

  13. Shido88
    • 2 years ago
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    the second one i found is 3/4 hope its right

  14. Shido88
    • 2 years ago
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    the third one i got: f(2c) = 4c

  15. Shido88
    • 2 years ago
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    and do you divide the 2c over ?

  16. Aylin
    • 2 years ago
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    I also got 3/4

  17. Shido88
    • 2 years ago
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    cool :D

  18. Aylin
    • 2 years ago
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    Well, with these problems you only need to simplify the right side, don't worry about the left side at all. In the third and fourth ones your answer will be in terms of c though.

  19. Shido88
    • 2 years ago
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    so is my answer for the third one okay ?

  20. Aylin
    • 2 years ago
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    Well, no.\[(2c)^{2}=4c^{2}\]and there is nothing in there to cancel it, so you should have a c^2 term.

  21. Shido88
    • 2 years ago
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    how did you get 2c^2 on the left side ?

  22. Shido88
    • 2 years ago
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    isn't it 2c ?

  23. Aylin
    • 2 years ago
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    \[f(2c)=3(2c)^{2}-4(2c)\]and\[(2c)^{2}=4c^{2}\]so\[f(2c)=3 \times 4c^{2}-4(2c)\]

  24. Shido88
    • 2 years ago
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    oh so you can't multiply the term -4 with 2c ?

  25. Aylin
    • 2 years ago
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    You can, but I was leaving it for you to do. :P

  26. Shido88
    • 2 years ago
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    ohhhh lol

  27. Shido88
    • 2 years ago
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    at first i thought u can make (2c)^2 = 4c and just X 3 = 12c

  28. Shido88
    • 2 years ago
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    i was wrong :|

  29. Aylin
    • 2 years ago
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    Pretty close, just forgot the ^2 part of it. :P

  30. Shido88
    • 2 years ago
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    u mean 12c^2 ?

  31. Aylin
    • 2 years ago
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    Yep

  32. Shido88
    • 2 years ago
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    but why ? :O isn't it already been done on the 2c^2 ?why ^2 another

  33. Shido88
    • 2 years ago
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    @___@

  34. Aylin
    • 2 years ago
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    Well\[(2c)^{2}\]is the same thing as\[2c \times 2c\]Does that make it more clear?

  35. Shido88
    • 2 years ago
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    does that make 4c ?

  36. Shido88
    • 2 years ago
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    and 4c x 3 = 12c lol ?

  37. Aylin
    • 2 years ago
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    \[2c \times 2c = 4c^{2}\]

  38. Shido88
    • 2 years ago
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    ohhh lol =___=

  39. Shido88
    • 2 years ago
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    omg...my mind is somewhere else today....sorry

  40. Aylin
    • 2 years ago
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    Mine is too, don't worry.

  41. Shido88
    • 2 years ago
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    naw, your good :D

  42. Shido88
    • 2 years ago
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    so once i got f(2c) = 12c^2 - 8c then what can i do next?

  43. Aylin
    • 2 years ago
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    Well, at this point all of the same powers of c are together, so you're done.

  44. Shido88
    • 2 years ago
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    what do you mean by "same powers of c are together" ? :d

  45. Aylin
    • 2 years ago
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    Well, there's only one c^2 term and only one c term. You can't combine the c^2 and the c terms, so there is nothing left to do.

  46. Shido88
    • 2 years ago
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    i see

  47. Shido88
    • 2 years ago
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    the fourth one im stuck completely :D

  48. Aylin
    • 2 years ago
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    Well, what is\[(c+1)^{2}\]?

  49. Shido88
    • 2 years ago
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    (c+1)(c+1)

  50. Aylin
    • 2 years ago
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    So FOIL it out! :P

  51. Shido88
    • 2 years ago
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    ohh let see

  52. Shido88
    • 2 years ago
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    c^2+2c+1 and i think u can factor it more right ?

  53. Aylin
    • 2 years ago
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    Well, we don't want to factor it right now. So now\[f(c+1)=3 \times (c^{2}+2c+1)-4 \times (c+1)\]Can you finish it from there?

  54. Shido88
    • 2 years ago
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    kk hold on

  55. Shido88
    • 2 years ago
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    i think it is : f(c+1)=3c^2 + 2c -1

  56. Aylin
    • 2 years ago
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    Yep!

  57. Shido88
    • 2 years ago
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    awesome! lol

  58. Shido88
    • 2 years ago
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    so is that it ? o_0

  59. Aylin
    • 2 years ago
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    Yep

  60. Shido88
    • 2 years ago
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    cool! thanks Aylin

  61. Aylin
    • 2 years ago
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    You're welcome.

  62. Shido88
    • 2 years ago
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    your really good in math :D genius maybe?

  63. Aylin
    • 2 years ago
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    Not really, I just want to teach math.

  64. Shido88
    • 2 years ago
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    btw are you in college?

  65. Shido88
    • 2 years ago
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    oh ! so your a teacher :D

  66. Shido88
    • 2 years ago
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    wow! how lucky i am :D

  67. Aylin
    • 2 years ago
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    Not yet. I'm a senior at RPI.

  68. Aylin
    • 2 years ago
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    But next year I hope to be a teacher.

  69. Shido88
    • 2 years ago
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    so your graduating next year ?

  70. Aylin
    • 2 years ago
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    In May

  71. Shido88
    • 2 years ago
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    oh wow, almost there!

  72. Shido88
    • 2 years ago
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    how many years did you spend in RPI ?

  73. Aylin
    • 2 years ago
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    The end of this year will make three years.

  74. Shido88
    • 2 years ago
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    that's really quick wow

  75. Shido88
    • 2 years ago
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    is this it ? "Rensselaer Polytechnic Institute" ?

  76. Aylin
    • 2 years ago
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    Yeah. Not really very fast though; I spent two years at another school first.

  77. Shido88
    • 2 years ago
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    I see, still not bad. I had a friend who spends 3 years at community college and transfer

  78. Shido88
    • 2 years ago
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    what's the GPA for acceptance in RPI?

  79. Aylin
    • 2 years ago
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    It was a community college that I came from, actually. From another college or from high school?

  80. Shido88
    • 2 years ago
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    another college

  81. Shido88
    • 2 years ago
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    yeah, everybody is doing community college first now aday, cuz it's so much cheaper :D

  82. Aylin
    • 2 years ago
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    Minimum is 3.0 Higher is better of course, but they also like it if you've been taking mostly science and math courses (or engineering if that's your major choice) if possible.

  83. Shido88
    • 2 years ago
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    make sense.

  84. Shido88
    • 2 years ago
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    well thanks so much for talking with me Aylin. I gotta get to dinner now :D

  85. Aylin
    • 2 years ago
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    Like if you took a lot of math/science courses and made mostly Bs, it would look better than if you had made As taking mostly things like Art or Chorus or History

  86. Aylin
    • 2 years ago
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    Bye

  87. Shido88
    • 2 years ago
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    anything with science and math is better...and it's the subjects that im most terrible at. WOW..

  88. Shido88
    • 2 years ago
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    well bye for now :d

  89. Aylin
    • 2 years ago
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    Well, the other thing is that RPI is about $60000 a year right now, so...

  90. Shido88
    • 2 years ago
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    your kidding me? no way

  91. Aylin
    • 2 years ago
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    http://admissions.rpi.edu/aid/index.html

  92. Shido88
    • 2 years ago
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    so how much for 1 semester of full time?

  93. Shido88
    • 2 years ago
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    omg wow...

  94. Aylin
    • 2 years ago
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    About half, but it depends on what your dining plan is, where you live, ect.

  95. Shido88
    • 2 years ago
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    omg so much debts...well but it's COLLEGE that we're talking about here so no suprise.. :|

  96. Shido88
    • 2 years ago
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    one time I read that article about this college couples graduated with over 200k debts scared the hell out of me :|

  97. Aylin
    • 2 years ago
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    I'm gonna have about $45K.

  98. Shido88
    • 2 years ago
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    did they tell you about the rate? or how much you have to pay back once your graduated ? I mean monthly?

  99. Aylin
    • 2 years ago
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    At some point probably. I don't remember what it is right now.

  100. Shido88
    • 2 years ago
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    oh i see, well i hope you can pay back all the debts without too much trouble :|

  101. Aylin
    • 2 years ago
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    I should be able to.

  102. Aylin
    • 2 years ago
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    Which year are you in?

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