Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Determine the value of f(-6), f(3/2), f(2c) and f(c+1), then simplify as much as possible Question : f(x) = 3x^2 - 4x

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

@Aylin help please :D
Well, in the first two, just take the appropriate number and plug it in where x is. Then simplify it down. For the third one (2c) replace x with 2c, then see what you get. Same for the fourth one. The first two are plug'n'chug, but if you need help with the second two I'll stick around.
the second two, just plug it in to every x in the problem ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Mhm. So f(2c) would like\[f(2c)=3 \times (2c)^{2}-4 \times (2c)\]
Ok let me try thanks!
ummm question
kinda dumb question but for the first one f(-6) i did -6=3(-6)^2-4(-6) -6=108+24 -6=132 then at this step do you add the 6 over or minus the 132 over ?? lol
it usually easier if one size has a (x)
Well, the left side is f(-6) not -6. So when you get to f(-6)=132, you are finished with that part.
Since you've found the value in the range (132) that corresponds to the value of -6 in the domain.
i see
the second one i found is 3/4 hope its right
the third one i got: f(2c) = 4c
and do you divide the 2c over ?
I also got 3/4
cool :D
Well, with these problems you only need to simplify the right side, don't worry about the left side at all. In the third and fourth ones your answer will be in terms of c though.
so is my answer for the third one okay ?
Well, no.\[(2c)^{2}=4c^{2}\]and there is nothing in there to cancel it, so you should have a c^2 term.
how did you get 2c^2 on the left side ?
isn't it 2c ?
\[f(2c)=3(2c)^{2}-4(2c)\]and\[(2c)^{2}=4c^{2}\]so\[f(2c)=3 \times 4c^{2}-4(2c)\]
oh so you can't multiply the term -4 with 2c ?
You can, but I was leaving it for you to do. :P
ohhhh lol
at first i thought u can make (2c)^2 = 4c and just X 3 = 12c
i was wrong :|
Pretty close, just forgot the ^2 part of it. :P
u mean 12c^2 ?
but why ? :O isn't it already been done on the 2c^2 ?why ^2 another
Well\[(2c)^{2}\]is the same thing as\[2c \times 2c\]Does that make it more clear?
does that make 4c ?
and 4c x 3 = 12c lol ?
\[2c \times 2c = 4c^{2}\]
ohhh lol =___= mind is somewhere else today....sorry
Mine is too, don't worry.
naw, your good :D
so once i got f(2c) = 12c^2 - 8c then what can i do next?
Well, at this point all of the same powers of c are together, so you're done.
what do you mean by "same powers of c are together" ? :d
Well, there's only one c^2 term and only one c term. You can't combine the c^2 and the c terms, so there is nothing left to do.
i see
the fourth one im stuck completely :D
Well, what is\[(c+1)^{2}\]?
So FOIL it out! :P
ohh let see
c^2+2c+1 and i think u can factor it more right ?
Well, we don't want to factor it right now. So now\[f(c+1)=3 \times (c^{2}+2c+1)-4 \times (c+1)\]Can you finish it from there?
kk hold on
i think it is : f(c+1)=3c^2 + 2c -1
awesome! lol
so is that it ? o_0
cool! thanks Aylin
You're welcome.
your really good in math :D genius maybe?
Not really, I just want to teach math.
btw are you in college?
oh ! so your a teacher :D
wow! how lucky i am :D
Not yet. I'm a senior at RPI.
But next year I hope to be a teacher.
so your graduating next year ?
In May
oh wow, almost there!
how many years did you spend in RPI ?
The end of this year will make three years.
that's really quick wow
is this it ? "Rensselaer Polytechnic Institute" ?
Yeah. Not really very fast though; I spent two years at another school first.
I see, still not bad. I had a friend who spends 3 years at community college and transfer
what's the GPA for acceptance in RPI?
It was a community college that I came from, actually. From another college or from high school?
another college
yeah, everybody is doing community college first now aday, cuz it's so much cheaper :D
Minimum is 3.0 Higher is better of course, but they also like it if you've been taking mostly science and math courses (or engineering if that's your major choice) if possible.
make sense.
well thanks so much for talking with me Aylin. I gotta get to dinner now :D
Like if you took a lot of math/science courses and made mostly Bs, it would look better than if you had made As taking mostly things like Art or Chorus or History
anything with science and math is better...and it's the subjects that im most terrible at. WOW..
well bye for now :d
Well, the other thing is that RPI is about $60000 a year right now, so...
your kidding me? no way
so how much for 1 semester of full time?
omg wow...
About half, but it depends on what your dining plan is, where you live, ect.
omg so much debts...well but it's COLLEGE that we're talking about here so no suprise.. :|
one time I read that article about this college couples graduated with over 200k debts scared the hell out of me :|
I'm gonna have about $45K.
did they tell you about the rate? or how much you have to pay back once your graduated ? I mean monthly?
At some point probably. I don't remember what it is right now.
oh i see, well i hope you can pay back all the debts without too much trouble :|
I should be able to.
Which year are you in?

Not the answer you are looking for?

Search for more explanations.

Ask your own question