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omgitsana

  • 3 years ago

what is the derivative of f(x)=x(2x-1)^(1/2)

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  1. omgitsana
    • 3 years ago
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    |dw:1358477486463:dw|

  2. seidi.yamauti
    • 3 years ago
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    product derivation f(x)=g(x).h(x) f'(x)=g'(x).h(x) + g(x)h'(x)

  3. seidi.yamauti
    • 3 years ago
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    where g(x)=x and h(x)=(2x-1)^1/2

  4. anonymous
    • 3 years ago
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    product rule for this one \[(fg)'=f'g+g'f\] with \[f(x)=x,f'(x)=1,g(x)=\sqrt{2x-1},g'(x)=\frac{1}{\sqrt{2x-1}}\]

  5. seidi.yamauti
    • 3 years ago
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    anyway, wolfram alpha would help you with that kind of question

  6. omgitsana
    • 3 years ago
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    aha i tried wolfram already but it was confusing. thanks guys

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