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zaynahf Group TitleBest ResponseYou've already chosen the best response.0
dw:1358478783791:dw
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
denominator changes sign at 0, numerator changes sign at 7, so divide up the real line into three intervals \\[(\infty, 0), (0,7),(7,\infty)\] then check on some interval to see if it is positive or negative if say \(x=10\) then both top and bottom are positive, so your answer is \[(\infty,0)\cup (7,\infty)\]
 one year ago
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