chronicle
Solve.
8x – 5 ≥ 27
a. x ≥ 4
b. x ≥ 11/4
c. x ≤ 4
d. x ≤ 11/4
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just like if it was an equal sign solve for x
seidi.yamauti
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/\ what he/she said
chronicle
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c?
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you don't have any negatives that you will multiply or divide both sides by so the greater than or equal to sign will not move.
khuangg
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Josh45680
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8x - 5 ≥ 27
+ 5 +5 (Add 5 to both side)
5+5 cancels out, you now have 8x/8 and 32/5. So, C. c. x ≤ 4
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\[8x-5\ge27 \]
+5 +5
\[8x \ge32\]
divide both sides by 8
\[x \ge32/8\]
x\[\ge4\]
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if it was a negative 8"" instead of positive then you would.....
\[-8x \ge32\]
divide by -8
\[x \le32\div-8\]
\[x \le-4\]
chronicle
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thanks do you know how to graph for the inequality?
chronicle
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–3x > 24
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do the same thing and divide both sides by (-3)
"this flips the sign the other way"
\[x <-8\]
now i'm pretty sure it doesn't want you to graph it on a plot but i'll show you both that and number line
chronicle
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|dw:1358479651620:dw|
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basically that shows the line and that everything to the left of it is where x is
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|dw:1358479785832:dw|
chronicle
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open circle or closed?
khuangg
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open circle
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that is on the number line and the closed circle means it does not exactly touch 8, but "x"=every number before -8. even. -7.9999999999 etc
chronicle
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thnx i have another
chronicle
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khuangg
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chronicle
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thnx
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no problem