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chronicle

  • 2 years ago

Solve. 8x – 5 ≥ 27 a. x ≥ 4 b. x ≥ 11/4 c. x ≤ 4 d. x ≤ 11/4

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  1. Honour
    • 2 years ago
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    just like if it was an equal sign solve for x

  2. seidi.yamauti
    • 2 years ago
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    /\ what he/she said

  3. chronicle
    • 2 years ago
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    c?

  4. Honour
    • 2 years ago
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    you don't have any negatives that you will multiply or divide both sides by so the greater than or equal to sign will not move.

  5. khuangg
    • 2 years ago
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  6. Josh45680
    • 2 years ago
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    8x - 5 ≥ 27 + 5 +5 (Add 5 to both side) 5+5 cancels out, you now have 8x/8 and 32/5. So, C. c. x ≤ 4

  7. Honour
    • 2 years ago
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    \[8x-5\ge27 \] +5 +5 \[8x \ge32\] divide both sides by 8 \[x \ge32/8\] x\[\ge4\]

  8. Honour
    • 2 years ago
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    if it was a negative 8"" instead of positive then you would..... \[-8x \ge32\] divide by -8 \[x \le32\div-8\] \[x \le-4\]

  9. chronicle
    • 2 years ago
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    thanks do you know how to graph for the inequality?

  10. chronicle
    • 2 years ago
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    –3x > 24

  11. Honour
    • 2 years ago
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    do the same thing and divide both sides by (-3) "this flips the sign the other way" \[x <-8\] now i'm pretty sure it doesn't want you to graph it on a plot but i'll show you both that and number line

  12. chronicle
    • 2 years ago
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  13. Honour
    • 2 years ago
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    |dw:1358479651620:dw|

  14. Honour
    • 2 years ago
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    basically that shows the line and that everything to the left of it is where x is

  15. Honour
    • 2 years ago
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    |dw:1358479785832:dw|

  16. chronicle
    • 2 years ago
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    open circle or closed?

  17. khuangg
    • 2 years ago
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    open circle

  18. Honour
    • 2 years ago
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    that is on the number line and the closed circle means it does not exactly touch 8, but "x"=every number before -8. even. -7.9999999999 etc

  19. chronicle
    • 2 years ago
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    thnx i have another

  20. chronicle
    • 2 years ago
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  21. khuangg
    • 2 years ago
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  22. chronicle
    • 2 years ago
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    thnx

  23. Honour
    • 2 years ago
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    no problem

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