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Solve. 8x – 5 ≥ 27 a. x ≥ 4 b. x ≥ 11/4 c. x ≤ 4 d. x ≤ 11/4

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just like if it was an equal sign solve for x
/\ what he/she said

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Other answers:

you don't have any negatives that you will multiply or divide both sides by so the greater than or equal to sign will not move.
8x - 5 ≥ 27 + 5 +5 (Add 5 to both side) 5+5 cancels out, you now have 8x/8 and 32/5. So, C. c. x ≤ 4
\[8x-5\ge27 \] +5 +5 \[8x \ge32\] divide both sides by 8 \[x \ge32/8\] x\[\ge4\]
if it was a negative 8"" instead of positive then you would..... \[-8x \ge32\] divide by -8 \[x \le32\div-8\] \[x \le-4\]
thanks do you know how to graph for the inequality?
–3x > 24
do the same thing and divide both sides by (-3) "this flips the sign the other way" \[x <-8\] now i'm pretty sure it doesn't want you to graph it on a plot but i'll show you both that and number line
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basically that shows the line and that everything to the left of it is where x is
open circle or closed?
open circle
that is on the number line and the closed circle means it does not exactly touch 8, but "x"=every number before -8. even. -7.9999999999 etc
thnx i have another
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no problem

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