## chronicle 2 years ago Solve. 8x – 5 ≥ 27 a. x ≥ 4 b. x ≥ 11/4 c. x ≤ 4 d. x ≤ 11/4

1. Honour

just like if it was an equal sign solve for x

2. seidi.yamauti

/\ what he/she said

3. chronicle

c?

4. Honour

you don't have any negatives that you will multiply or divide both sides by so the greater than or equal to sign will not move.

5. khuangg

6. Josh45680

8x - 5 ≥ 27 + 5 +5 (Add 5 to both side) 5+5 cancels out, you now have 8x/8 and 32/5. So, C. c. x ≤ 4

7. Honour

\[8x-5\ge27 \] +5 +5 \[8x \ge32\] divide both sides by 8 \[x \ge32/8\] x\[\ge4\]

8. Honour

if it was a negative 8"" instead of positive then you would..... \[-8x \ge32\] divide by -8 \[x \le32\div-8\] \[x \le-4\]

9. chronicle

thanks do you know how to graph for the inequality?

10. chronicle

–3x > 24

11. Honour

do the same thing and divide both sides by (-3) "this flips the sign the other way" \[x <-8\] now i'm pretty sure it doesn't want you to graph it on a plot but i'll show you both that and number line

12. chronicle

13. Honour

|dw:1358479651620:dw|

14. Honour

basically that shows the line and that everything to the left of it is where x is

15. Honour

|dw:1358479785832:dw|

16. chronicle

open circle or closed?

17. khuangg

open circle

18. Honour

that is on the number line and the closed circle means it does not exactly touch 8, but "x"=every number before -8. even. -7.9999999999 etc

19. chronicle

thnx i have another

20. chronicle

21. khuangg

22. chronicle

thnx

23. Honour

no problem