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itsladyrw

  • 3 years ago

Simplify completely, 4x^2 - 32x + 48 / 3x^2 - 17x - 6

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  1. khuangg
    • 3 years ago
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    \[=\frac{ 4x^2-32x+48 }{ 3x^2-17x-6 }\] \[= \frac{ 4(x^2-8x+12) }{ 3x^2-17x-6 }\] \[= \frac{ 4(x-6)(x-2) }{ (x-6)(3x-1) }\] \[=\frac{ 4(x-2) }{ 3x-1 }\] there you go!

  2. itsladyrw
    • 3 years ago
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    THANKS YOU<3

  3. khuangg
    • 3 years ago
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    no problem ^^

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