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- anonymous

I was asked to write a program that finds the solutions, if any, to a given quadratic equation. My code is below. I have two issues: First When i input for example, a=3, b=4, c=5 the result prints" The roots are -nan and -nan" Secondly, I am to ensure that division by 0 is not permitted and the discriminant b^2-4ac cannot be negative. I am having a hard time with this bit. Could you help me solve this part?

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- anonymous

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

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- tyteen4a03

Is there any code handy?

- anonymous

@tyteen4a03
/* This program takes in the values of the three coefficients a, b, and c as a screen input from
the user. It then determines the roots of the quadratic equation using the formula ax^2 + bx + c = 0.
The two roots are then outputted using the 'cout' command. */
#include
#include
using namespace std;
int main(){
/* Declaring and initializing our variables a, b,c a and disc which is short for the discriminant, positive_root and negative_root*/
float a,b,c,disc,positive_root,negative_root;
cout << "Enter the 3 coefficients a, b, c : " << endl;
cin>>a>>b>>c;
if(!a){
if(!b)
cout << "Both a and b cannot be 0 in ax^2 + bx + c = 0" << "\n";
else
{
disc=-c/b;
cout << "The solution of the linear equation is : " << d << endl;
}
}
else
{
disc=b*b-4*a*c;
if(d>0)
positive_root=(-b+sqrt(d))/(2*a);
negative_root=(-b-sqrt(d))/(2*a);
cout << "The first root = " << positive_root << endl;
cout << "The second root = " << negative_root << endl;
}
getch();
return 0;
}

- anonymous

This is a modified code of someone else's

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