anonymous
  • anonymous
I was asked to write a program that finds the solutions, if any, to a given quadratic equation. My code is below. I have two issues: First When i input for example, a=3, b=4, c=5 the result prints" The roots are -nan and -nan" Secondly, I am to ensure that division by 0 is not permitted and the discriminant b^2-4ac cannot be negative. I am having a hard time with this bit. Could you help me solve this part?
Computer Science
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
tyteen4a03
  • tyteen4a03
Is there any code handy?
anonymous
  • anonymous
@tyteen4a03 /* This program takes in the values of the three coefficients a, b, and c as a screen input from the user. It then determines the roots of the quadratic equation using the formula ax^2 + bx + c = 0. The two roots are then outputted using the 'cout' command. */ #include #include using namespace std; int main(){ /* Declaring and initializing our variables a, b,c a and disc which is short for the discriminant, positive_root and negative_root*/ float a,b,c,disc,positive_root,negative_root; cout << "Enter the 3 coefficients a, b, c : " << endl; cin>>a>>b>>c; if(!a){ if(!b) cout << "Both a and b cannot be 0 in ax^2 + bx + c = 0" << "\n"; else { disc=-c/b; cout << "The solution of the linear equation is : " << d << endl; } } else { disc=b*b-4*a*c; if(d>0) positive_root=(-b+sqrt(d))/(2*a); negative_root=(-b-sqrt(d))/(2*a); cout << "The first root = " << positive_root << endl; cout << "The second root = " << negative_root << endl; } getch(); return 0; }
anonymous
  • anonymous
This is a modified code of someone else's

Looking for something else?

Not the answer you are looking for? Search for more explanations.