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kirbykirby

Verifying the property of the Gamma function: Gamma(n) = (n-1)!

  • one year ago
  • one year ago

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  1. kirbykirby
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    \[\Gamma (\alpha)=\int\limits_{0}^{\infty}x^{\alpha-1}e^{-x}dx\] I understand how to get to the relationship \[\Gamma (\alpha)=(\alpha-1)\Gamma (\alpha-1)\] for any alpha >1 But I'm not sure how t get to :\[\Gamma (n)=(n-1)!\] for n is a positive integer

    • one year ago
  2. satellite73
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    really? you have done all the hard work!

    • one year ago
  3. kirbykirby
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    I dunno why I can't see this.. my brain is fried probably from doing the first part LOL

    • one year ago
  4. satellite73
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    yeah i guess so

    • one year ago
  5. satellite73
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    \(n!=n(n-1)!\)

    • one year ago
  6. satellite73
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    that is \(n!\) can be defined as the recursion \(1!=1\) and \(n!=n(n-1)!\)

    • one year ago
  7. kirbykirby
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    OH i see right!! Oh thank you. Haha oh my that was fairly simple :P

    • one year ago
  8. kirbykirby
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    Thanks :)!!

    • one year ago
  9. satellite73
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    yeah way way more simple than showing \(\Gamma(\alpha)=(\alpha-1)\Gamma(\alpha -1)\)

    • one year ago
  10. kirbykirby
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    For sure!!!

    • one year ago
  11. satellite73
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    yw

    • one year ago
  12. satellite73
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    like opening the jar after someone already loosened it

    • one year ago
  13. kirbykirby
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    @satellite73 I couldn't help but wonder how do you keep your equations on the same line?

    • one year ago
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