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Shido88

  • 2 years ago

h(3) h(x)= 5|x|/x

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  1. Shido88
    • 2 years ago
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    @Aylin

  2. Shido88
    • 2 years ago
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    i plug this one in calculator and got 5 as final answer

  3. Aylin
    • 2 years ago
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    That looks right.

  4. Shido88
    • 2 years ago
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    alright cool :D

  5. Shido88
    • 2 years ago
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    for the next one it's asking for h(-2/3) but you can't use a negative for absolute value right? or is it ?

  6. Shido88
    • 2 years ago
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    umm why over 5 ? isn't it over -2/3 ?

  7. Aylin
    • 2 years ago
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    @Shido88 Sorry, I got distracted. Back now. Absolute value as a function either leaves the thing inside of it alone if it is 0 or positive, or multiplies it b negative 1 if it is negative. So |x|=x IF x is greater than or equal to 0, and |x| = -x IF x is less than 0. So for h(-2/3) you would have\[h(\frac{-2}{3})=5\frac{|\frac{ - 2}{3}|}{\frac{-2}{3}}=5\frac{\frac{2}{3}}{\frac{-2}{3}}\]

  8. Aylin
    • 2 years ago
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    Hmm, looks like the negative signs didn't display properly... Well, the 2s that are shifted way over to the right are supposed to have negative signs in front of them.

  9. Shido88
    • 2 years ago
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    so basictly anything negative inside the absolute value will turn into positive ?

  10. Aylin
    • 2 years ago
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    Yep!

  11. Shido88
    • 2 years ago
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    and once u turn the negative into positive then the absolute value sign goes away ?

  12. Aylin
    • 2 years ago
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    In this case, yes.

  13. Shido88
    • 2 years ago
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    what about h(3a) ?

  14. Aylin
    • 2 years ago
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    Ahh, well this depends on if a is positive or not. :P Find the answer for if a is positive, and then the answer for if a is negative. Then you say which one it is based on a.

  15. Shido88
    • 2 years ago
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    hmm ? what ? lol

  16. Aylin
    • 2 years ago
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    If \[a \ge 0\]then\[h(3a)=5\]and if\[a < 0\]then\[h(3a)=-5\]

  17. Shido88
    • 2 years ago
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    i see

  18. Shido88
    • 2 years ago
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    what do i have to do to know if a>0 ?

  19. Shido88
    • 2 years ago
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    how did you get h(3a)= 5 ? do you just cancel out the 3a ?

  20. Aylin
    • 2 years ago
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    Yeah.\[5\frac{3a}{3a}=5\]

  21. Shido88
    • 2 years ago
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    oh i see

  22. Shido88
    • 2 years ago
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    so if it was h(a-2) would the final answer be 5 anyway ?

  23. Aylin
    • 2 years ago
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    Either 5 or -5, depending on a.

  24. Shido88
    • 2 years ago
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    ok!

  25. Shido88
    • 2 years ago
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    gtg now, thanks again for helping me Aylin :)

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