## Shido88 Group Title h(3) h(x)= 5|x|/x one year ago one year ago

1. Shido88

@Aylin

2. Shido88

i plug this one in calculator and got 5 as final answer

3. Aylin

That looks right.

4. Shido88

alright cool :D

5. Shido88

for the next one it's asking for h(-2/3) but you can't use a negative for absolute value right? or is it ?

6. Shido88

umm why over 5 ? isn't it over -2/3 ?

7. Aylin

@Shido88 Sorry, I got distracted. Back now. Absolute value as a function either leaves the thing inside of it alone if it is 0 or positive, or multiplies it b negative 1 if it is negative. So |x|=x IF x is greater than or equal to 0, and |x| = -x IF x is less than 0. So for h(-2/3) you would have$h(\frac{-2}{3})=5\frac{|\frac{ - 2}{3}|}{\frac{-2}{3}}=5\frac{\frac{2}{3}}{\frac{-2}{3}}$

8. Aylin

Hmm, looks like the negative signs didn't display properly... Well, the 2s that are shifted way over to the right are supposed to have negative signs in front of them.

9. Shido88

so basictly anything negative inside the absolute value will turn into positive ?

10. Aylin

Yep!

11. Shido88

and once u turn the negative into positive then the absolute value sign goes away ?

12. Aylin

In this case, yes.

13. Shido88

14. Aylin

Ahh, well this depends on if a is positive or not. :P Find the answer for if a is positive, and then the answer for if a is negative. Then you say which one it is based on a.

15. Shido88

hmm ? what ? lol

16. Aylin

If $a \ge 0$then$h(3a)=5$and if$a < 0$then$h(3a)=-5$

17. Shido88

i see

18. Shido88

what do i have to do to know if a>0 ?

19. Shido88

how did you get h(3a)= 5 ? do you just cancel out the 3a ?

20. Aylin

Yeah.$5\frac{3a}{3a}=5$

21. Shido88

oh i see

22. Shido88

so if it was h(a-2) would the final answer be 5 anyway ?

23. Aylin

Either 5 or -5, depending on a.

24. Shido88

ok!

25. Shido88

gtg now, thanks again for helping me Aylin :)