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Shido88 Group Title

h(3) h(x)= 5|x|/x

  • one year ago
  • one year ago

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  1. Shido88 Group Title
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    @Aylin

    • one year ago
  2. Shido88 Group Title
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    i plug this one in calculator and got 5 as final answer

    • one year ago
  3. Aylin Group Title
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    That looks right.

    • one year ago
  4. Shido88 Group Title
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    alright cool :D

    • one year ago
  5. Shido88 Group Title
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    for the next one it's asking for h(-2/3) but you can't use a negative for absolute value right? or is it ?

    • one year ago
  6. Shido88 Group Title
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    umm why over 5 ? isn't it over -2/3 ?

    • one year ago
  7. Aylin Group Title
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    @Shido88 Sorry, I got distracted. Back now. Absolute value as a function either leaves the thing inside of it alone if it is 0 or positive, or multiplies it b negative 1 if it is negative. So |x|=x IF x is greater than or equal to 0, and |x| = -x IF x is less than 0. So for h(-2/3) you would have\[h(\frac{-2}{3})=5\frac{|\frac{ - 2}{3}|}{\frac{-2}{3}}=5\frac{\frac{2}{3}}{\frac{-2}{3}}\]

    • one year ago
  8. Aylin Group Title
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    Hmm, looks like the negative signs didn't display properly... Well, the 2s that are shifted way over to the right are supposed to have negative signs in front of them.

    • one year ago
  9. Shido88 Group Title
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    so basictly anything negative inside the absolute value will turn into positive ?

    • one year ago
  10. Aylin Group Title
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    Yep!

    • one year ago
  11. Shido88 Group Title
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    and once u turn the negative into positive then the absolute value sign goes away ?

    • one year ago
  12. Aylin Group Title
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    In this case, yes.

    • one year ago
  13. Shido88 Group Title
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    what about h(3a) ?

    • one year ago
  14. Aylin Group Title
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    Ahh, well this depends on if a is positive or not. :P Find the answer for if a is positive, and then the answer for if a is negative. Then you say which one it is based on a.

    • one year ago
  15. Shido88 Group Title
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    hmm ? what ? lol

    • one year ago
  16. Aylin Group Title
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    If \[a \ge 0\]then\[h(3a)=5\]and if\[a < 0\]then\[h(3a)=-5\]

    • one year ago
  17. Shido88 Group Title
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    i see

    • one year ago
  18. Shido88 Group Title
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    what do i have to do to know if a>0 ?

    • one year ago
  19. Shido88 Group Title
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    how did you get h(3a)= 5 ? do you just cancel out the 3a ?

    • one year ago
  20. Aylin Group Title
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    Yeah.\[5\frac{3a}{3a}=5\]

    • one year ago
  21. Shido88 Group Title
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    oh i see

    • one year ago
  22. Shido88 Group Title
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    so if it was h(a-2) would the final answer be 5 anyway ?

    • one year ago
  23. Aylin Group Title
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    Either 5 or -5, depending on a.

    • one year ago
  24. Shido88 Group Title
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    ok!

    • one year ago
  25. Shido88 Group Title
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    gtg now, thanks again for helping me Aylin :)

    • one year ago
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