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thatjacksonguy

  • 3 years ago

Find a quadratic function in standard form that has the following points: (1, -2); (2, -2); (3, -4).

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  1. tkhunny
    • 3 years ago
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    Can you find the Axis of Symmetry without doing any algebra?

  2. thatjacksonguy
    • 3 years ago
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    im not sure

  3. tkhunny
    • 3 years ago
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    Shall we guess that (0,-4) is yet another point?

  4. tkhunny
    • 3 years ago
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    Axis of Symmetry is x = 3/2. Please tell me why?

  5. tkhunny
    • 3 years ago
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    Quadratic Function in Standard Form: \(f(x) = ax^{2} + bx + c\) From your three points: (1, -2); (2, -2); (3, -4). We have: \(f(x) = a(1)^{2} + b(1) + c = -2\) \(f(x) = a(2)^{2} + b(2) + c = -2\) \(f(x) = a(3)^{2} + b(3) + c = -4\) And you have some algebra in your future!

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