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Need help with a problem. Just tell me where to go with it; I don't want anyone to solve it for me. Just confused... I tried the counting principle but it didn't work.
"Suppose you roll two number cubes and pick a letter of the alphabet at random. Find the probability you roll two even numbers and pick one of the vowels a, e, i, o, or u"
 one year ago
 one year ago
Need help with a problem. Just tell me where to go with it; I don't want anyone to solve it for me. Just confused... I tried the counting principle but it didn't work. "Suppose you roll two number cubes and pick a letter of the alphabet at random. Find the probability you roll two even numbers and pick one of the vowels a, e, i, o, or u"
 one year ago
 one year ago

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whatisthequestionBest ResponseYou've already chosen the best response.1
what is the probability of rolling an even number on one of the cubes? What is the probability of choosing one of the vowels? I mean on there own
 one year ago

KazehayaBest ResponseYou've already chosen the best response.0
Probability of choosing an even number on either cube is 1/2, and the probability for choosing a vowel is 5/26. Do I just add them together?
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.1
are they independent events?
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.1
well they cannot impact each other so they are independent events
 one year ago

KazehayaBest ResponseYou've already chosen the best response.0
right. And the probability for rolling to even numbers is 1/4
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.1
Unfortunately I do not remeber the formula for independent events so I would check you textbook or formula sheet . . . if I had to guess I would say it is multiplying them together so \[\frac{ 1 }{ 2 }*\frac{ 1 }{ 2 }*\frac{ 5 }{ 26 }\]
 one year ago

KazehayaBest ResponseYou've already chosen the best response.0
Ah! That's it. Thanks.
 one year ago

whatisthequestionBest ResponseYou've already chosen the best response.1
yea a quick way to see that it is not adding is that it would give you over 100% chance of success anyways don't forget to close the question
 one year ago
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