A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Is it possible for a triangle to have sides with the given lengths: 5in, 8in, & 15in?
 one year ago
Is it possible for a triangle to have sides with the given lengths: 5in, 8in, & 15in?

This Question is Closed

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358502234947:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0the sides wont all meet

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0How about 10cm,12cm,20cm? @UnkleRhaukus

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.2Three things must be true for the sides: Two sides added together must be larger than the third side. a+b>c, a+c>b, b+c>a So, for your first one: a=5, b=8, c=15 5+8=13 > 15 < false 8+15=23 > 5 < true 5+15=20 > 8 < true Because there is one false, the sides are invalid.

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0How about the second one... im not sure howt o do the formula though.. @PhoenixFire

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.2a=10 b=12 c=20 Check the three inequalities I gave you and see if any result in a false. If so, the triangle is invalid. If they are all true, then it is a valid triangle.

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0It isn't possible. thats what i got.

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.210+12=22 > 20 < true 10+20=30 > 12 < true 12+20=32 > 10 < true The triangle is VALID.

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0I dont understand though.

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0Nevermind! i understand it now.. it has to be greater then the number. thats the part i wasn't understanding. i was doing it the opposite way thats why it through me off . thank you so much!! :D

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.2haha. No problems.

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0I have 2 more questions that i need help on, do you mind giving me a hand? @PhoenixFire

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0Triangle PQR has medians QM and PN that intersect at Z. if Zm=4, what is QZ and QM. @PhoenixFire

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.2dw:1358503491884:dw Supposedly ZM is half the length of QZ: dw:1358503968318:dw So if ZM=4 then QZ=8 which means QM=ZM+QZ=4+8=12 @UnkleRhaukus If you can validate this. I'm not a triangle expert.

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.2It's a property of medians and centroids I believe. I'm not 100% certain on this.

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0Thats what i was thinking too. that it was half of that. so whats QZ and QM then?

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.2I gave the answer in my post. ZM=Centroid to midpoint=a=4 QZ=vertex to centroid=2a=8 QM=vertex to midpoint=2a+a=12

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0QZ=8 and QM=12 is this right?

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0okay i have one more.... this one is hard i think lol

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358428925101:dw @PhoenixFire

barnoldwrl
 one year ago
Best ResponseYou've already chosen the best response.0you there? @phoenixfire

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.2Thinking. Sorry. :P

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.2I'm guessing the 2x line goes between midpoints of those sides?

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.2So what I've gathered is that the line connecting two midpoints is half the size of the third side. \[2x={1 \over 2}(x+12)\] So, solve for x I guess. \[4x=x+12\]\[3x=12\]\[x=4\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.