anonymous
  • anonymous
Is it possible for a triangle to have sides with the given lengths: 5in, 8in, & 15in?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@hba
UnkleRhaukus
  • UnkleRhaukus
|dw:1358502234947:dw|
anonymous
  • anonymous
??

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More answers

UnkleRhaukus
  • UnkleRhaukus
the sides wont all meet
anonymous
  • anonymous
How about 10cm,12cm,20cm? @UnkleRhaukus
PhoenixFire
  • PhoenixFire
Three things must be true for the sides: Two sides added together must be larger than the third side. a+b>c, a+c>b, b+c>a So, for your first one: a=5, b=8, c=15 5+8=13 > 15 <---- false 8+15=23 > 5 <---- true 5+15=20 > 8 <---- true Because there is one false, the sides are invalid.
anonymous
  • anonymous
How about the second one... im not sure howt o do the formula though.. @PhoenixFire
UnkleRhaukus
  • UnkleRhaukus
Try construction
PhoenixFire
  • PhoenixFire
a=10 b=12 c=20 Check the three inequalities I gave you and see if any result in a false. If so, the triangle is invalid. If they are all true, then it is a valid triangle.
anonymous
  • anonymous
It isn't possible. thats what i got.
anonymous
  • anonymous
@PhoenixFire
PhoenixFire
  • PhoenixFire
10+12=22 > 20 <---- true 10+20=30 > 12 <---- true 12+20=32 > 10 <---- true The triangle is VALID.
anonymous
  • anonymous
I dont understand though.
anonymous
  • anonymous
Nevermind! i understand it now.. it has to be greater then the number. thats the part i wasn't understanding. i was doing it the opposite way thats why it through me off . thank you so much!! :D
PhoenixFire
  • PhoenixFire
haha. No problems.
anonymous
  • anonymous
I have 2 more questions that i need help on, do you mind giving me a hand? @PhoenixFire
PhoenixFire
  • PhoenixFire
sure.
anonymous
  • anonymous
Triangle PQR has medians QM and PN that intersect at Z. if Zm=4, what is QZ and QM. @PhoenixFire
PhoenixFire
  • PhoenixFire
|dw:1358503491884:dw| Supposedly ZM is half the length of QZ: |dw:1358503968318:dw| So if ZM=4 then QZ=8 which means QM=ZM+QZ=4+8=12 @UnkleRhaukus If you can validate this. I'm not a triangle expert.
PhoenixFire
  • PhoenixFire
It's a property of medians and centroids I believe. I'm not 100% certain on this.
anonymous
  • anonymous
Thats what i was thinking too. that it was half of that. so whats QZ and QM then?
PhoenixFire
  • PhoenixFire
I gave the answer in my post. ZM=Centroid to midpoint=a=4 QZ=vertex to centroid=2a=8 QM=vertex to midpoint=2a+a=12
anonymous
  • anonymous
QZ=8 and QM=12 is this right?
PhoenixFire
  • PhoenixFire
Yes
anonymous
  • anonymous
okay i have one more.... this one is hard i think lol
anonymous
  • anonymous
|dw:1358428925101:dw| @PhoenixFire
PhoenixFire
  • PhoenixFire
find X?
anonymous
  • anonymous
Yes, sorry.
anonymous
  • anonymous
you there? @phoenixfire
PhoenixFire
  • PhoenixFire
Thinking. Sorry. :P
anonymous
  • anonymous
Its okay.
PhoenixFire
  • PhoenixFire
I'm guessing the 2x line goes between midpoints of those sides?
anonymous
  • anonymous
Yeah
PhoenixFire
  • PhoenixFire
So what I've gathered is that the line connecting two midpoints is half the size of the third side. \[2x={1 \over 2}(x+12)\] So, solve for x I guess. \[4x=x+12\]\[3x=12\]\[x=4\]
anonymous
  • anonymous
Thank you!!!!
PhoenixFire
  • PhoenixFire
No problem. :)

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