## Kazehaya 2 years ago "A panel of judges must consist of four students and three teachers. A list of potential judges includes six students and five teachers. How many different panels could be created from this list?" How do I solve this? Not looking for the actual answer, just looking for how to solve it. I've spent just about an hour on this question...

1. PhoenixFire

It would be: the amount of ways you can pick 3 teachers from 5 multiplied by the amount of ways you can pick 4 students from 6.

2. PhoenixFire

For example: If there are 2 red balls and 3 green balls. how many ways can you pick 1 red and 1 green. How many ways can you pick 1 red from 2? .... 2 How many ways can you pick 1 green from 3? ..... 3 2*3=6 ways. |dw:1358504712847:dw|

3. Kazehaya

Oh my...

4. Kazehaya

I see. Another question: what are the "!"s next to numbers in a combination for?

5. PhoenixFire

I'm guessing you mean like: \(n!\) Means factorial.

6. PhoenixFire

\[5!=5*4*3*2*1\]

7. Kazehaya

Oh, I get it.

8. Kazehaya

Right... thanks.

9. PhoenixFire

No problem.