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 one year ago
"A panel of judges must consist of four students and three teachers. A list of potential judges includes six students and five teachers. How many different panels could be created from this list?"
How do I solve this? Not looking for the actual answer, just looking for how to solve it. I've spent just about an hour on this question...
 one year ago
"A panel of judges must consist of four students and three teachers. A list of potential judges includes six students and five teachers. How many different panels could be created from this list?" How do I solve this? Not looking for the actual answer, just looking for how to solve it. I've spent just about an hour on this question...

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PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.1It would be: the amount of ways you can pick 3 teachers from 5 multiplied by the amount of ways you can pick 4 students from 6.

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.1For example: If there are 2 red balls and 3 green balls. how many ways can you pick 1 red and 1 green. How many ways can you pick 1 red from 2? .... 2 How many ways can you pick 1 green from 3? ..... 3 2*3=6 ways. dw:1358504712847:dw

Kazehaya
 one year ago
Best ResponseYou've already chosen the best response.0I see. Another question: what are the "!"s next to numbers in a combination for?

PhoenixFire
 one year ago
Best ResponseYou've already chosen the best response.1I'm guessing you mean like: \(n!\) Means factorial.
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