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- anonymous

"A panel of judges must consist of four students and three teachers. A list of potential judges includes six students and five teachers. How many different panels could be created from this list?"
How do I solve this? Not looking for the actual answer, just looking for how to solve it. I've spent just about an hour on this question...

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- anonymous

- jamiebookeater

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- PhoenixFire

It would be: the amount of ways you can pick 3 teachers from 5 multiplied by the amount of ways you can pick 4 students from 6.

- PhoenixFire

For example: If there are 2 red balls and 3 green balls. how many ways can you pick 1 red and 1 green.
How many ways can you pick 1 red from 2? .... 2
How many ways can you pick 1 green from 3? ..... 3
2*3=6 ways.
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- anonymous

Oh my...

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- anonymous

I see. Another question: what are the "!"s next to numbers in a combination for?

- PhoenixFire

I'm guessing you mean like: \(n!\)
Means factorial.

- PhoenixFire

\[5!=5*4*3*2*1\]

- anonymous

Oh, I get it.

- anonymous

Right... thanks.

- PhoenixFire

No problem.

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