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anonymous
 4 years ago
"A panel of judges must consist of four students and three teachers. A list of potential judges includes six students and five teachers. How many different panels could be created from this list?"
How do I solve this? Not looking for the actual answer, just looking for how to solve it. I've spent just about an hour on this question...
anonymous
 4 years ago
"A panel of judges must consist of four students and three teachers. A list of potential judges includes six students and five teachers. How many different panels could be created from this list?" How do I solve this? Not looking for the actual answer, just looking for how to solve it. I've spent just about an hour on this question...

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PhoenixFire
 4 years ago
Best ResponseYou've already chosen the best response.1It would be: the amount of ways you can pick 3 teachers from 5 multiplied by the amount of ways you can pick 4 students from 6.

PhoenixFire
 4 years ago
Best ResponseYou've already chosen the best response.1For example: If there are 2 red balls and 3 green balls. how many ways can you pick 1 red and 1 green. How many ways can you pick 1 red from 2? .... 2 How many ways can you pick 1 green from 3? ..... 3 2*3=6 ways. dw:1358504712847:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I see. Another question: what are the "!"s next to numbers in a combination for?

PhoenixFire
 4 years ago
Best ResponseYou've already chosen the best response.1I'm guessing you mean like: \(n!\) Means factorial.
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