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Kazehaya

  • 2 years ago

"A panel of judges must consist of four students and three teachers. A list of potential judges includes six students and five teachers. How many different panels could be created from this list?" How do I solve this? Not looking for the actual answer, just looking for how to solve it. I've spent just about an hour on this question...

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  1. PhoenixFire
    • 2 years ago
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    It would be: the amount of ways you can pick 3 teachers from 5 multiplied by the amount of ways you can pick 4 students from 6.

  2. PhoenixFire
    • 2 years ago
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    For example: If there are 2 red balls and 3 green balls. how many ways can you pick 1 red and 1 green. How many ways can you pick 1 red from 2? .... 2 How many ways can you pick 1 green from 3? ..... 3 2*3=6 ways. |dw:1358504712847:dw|

  3. Kazehaya
    • 2 years ago
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    Oh my...

  4. Kazehaya
    • 2 years ago
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    I see. Another question: what are the "!"s next to numbers in a combination for?

  5. PhoenixFire
    • 2 years ago
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    I'm guessing you mean like: \(n!\) Means factorial.

  6. PhoenixFire
    • 2 years ago
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    \[5!=5*4*3*2*1\]

  7. Kazehaya
    • 2 years ago
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    Oh, I get it.

  8. Kazehaya
    • 2 years ago
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    Right... thanks.

  9. PhoenixFire
    • 2 years ago
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    No problem.

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