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"A panel of judges must consist of four students and three teachers. A list of potential judges includes six students and five teachers. How many different panels could be created from this list?" How do I solve this? Not looking for the actual answer, just looking for how to solve it. I've spent just about an hour on this question...

Pre-Algebra
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It would be: the amount of ways you can pick 3 teachers from 5 multiplied by the amount of ways you can pick 4 students from 6.
For example: If there are 2 red balls and 3 green balls. how many ways can you pick 1 red and 1 green. How many ways can you pick 1 red from 2? .... 2 How many ways can you pick 1 green from 3? ..... 3 2*3=6 ways. |dw:1358504712847:dw|
Oh my...

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Other answers:

I see. Another question: what are the "!"s next to numbers in a combination for?
I'm guessing you mean like: \(n!\) Means factorial.
\[5!=5*4*3*2*1\]
Oh, I get it.
Right... thanks.
No problem.

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