Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
msingh
Group Title
two equal circles of radius 5 cm have two common tangent AB and CD which touch the circle on A, C and B, D respectively and if CD = 24 cm, find the length of AB.
 one year ago
 one year ago
msingh Group Title
two equal circles of radius 5 cm have two common tangent AB and CD which touch the circle on A, C and B, D respectively and if CD = 24 cm, find the length of AB.
 one year ago
 one year ago

This Question is Closed

msingh Group TitleBest ResponseYou've already chosen the best response.0
dw:1358505912245:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
interesting :)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
can i know what did you attempt here?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
can i know what was your attempt here?
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
in a traingle bcd, i apply pythagoras theorem
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
CD^2=BC^2+BD^2
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
but how you got CD?
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
it is given
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
24^2=BC^2+5^2
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
ok you see for getting AB we need to take one more triangle.can you tell which one that will be?
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
i don't know
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
well try to think of a triangle containing AB
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
a right angled one
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
plse see this diagram..
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
yep i saw
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
do u think taking a triangle BCD is right
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
okay...wait ..the other triangle be ABC.
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
wait a sec...
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
to make things clear join OB
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
where O is centre
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
in btw hw did u get bcd as rt angled ? :P
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
that's why i m saying i m wrong , we can't take tr.BCD
 one year ago

Anuska Group TitleBest ResponseYou've already chosen the best response.0
ob n od shld b joined
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
join OA also
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i will try my best to draw that
 one year ago

Anuska Group TitleBest ResponseYou've already chosen the best response.0
yea thn tk d triangle AOD
 one year ago

Anuska Group TitleBest ResponseYou've already chosen the best response.0
& thn apply d theorem
 one year ago

Anuska Group TitleBest ResponseYou've already chosen the best response.0
ad^2= oa^2+od^2
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
@msingh i hand over this one to her :) seeya
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
vat is value of AD and OA
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
OA is not a radius
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
well msing we need to use property of tangents from same point i guess
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
lemme try this on properly ...
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
*on paper
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
draw a segment joining the centers.
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
dw:1358508030734:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
nice one @sirm3d
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
dw:1358508121964:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
isnt OO'=AB @sirm3d ?
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
that's right. O'O = AB
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
ABOO' is a rectangle it seems
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
my first attempt on this question wasnt as succesful as i thought .well this one was nice :)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
@msingh any doubts here?
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
when the triangle are congruent, vat after that
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
AO'=BO =5cm CD=24cm
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
find OO' using that !!
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
CP= CD/2=24/2=12
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
OP=12 because the triangles O'CP and ODP are congruent
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
oops. i meant CP=DP =12
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
Find OP 2OP =OO'
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
use pythagorean theorem to find the length of hypotenuse OP of triangle ODP
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
OO' = 26cm=AB
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
right you are!
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
:) WELL DONE
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
thank u @AravindG and @sirm3d
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i liked @sirm3d novelty :P
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.