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|dw:1358505912245:dw|

interesting :)

can i know what did you attempt here?

can i know what was your attempt here?

in a traingle bcd, i apply pythagoras theorem

CD^2=BC^2+BD^2

but how you got CD?

it is given

24^2=BC^2+5^2

ok

ok you see for getting AB we need to take one more triangle.can you tell which one that will be?

i don't know

well try to think of a triangle containing AB

a right angled one

plse see this diagram..

yep i saw

do u think taking a triangle BCD is right

okay...wait ..the other triangle be ABC.

wait a sec...

to make things clear join OB

where O is centre

in btw hw did u get bcd as rt angled ? :P

that's why i m saying i m wrong , we can't take tr.BCD

ob n od shld b joined

yeh :)

join OA also

i will try my best to draw that

yea thn tk d triangle AOD

& thn apply d theorem

ad^2= oa^2+od^2

vat is value of AD and OA

oa is 5

how

OA is not a radius

well msing we need to use property of tangents from same point i guess

lemme try this on properly ...

*on paper

draw a segment joining the centers.

|dw:1358508030734:dw|

|dw:1358508121964:dw|

that's right. O'O = AB

ABOO' is a rectangle it seems

my first attempt on this question wasnt as succesful as i thought .well this one was nice :)

when the triangle are congruent,
vat after that

AO'=BO =5cm
CD=24cm

find OO' using that !!

CP= CD/2=24/2=12

OP=12 because the triangles O'CP and ODP are congruent

oops. i meant CP=DP =12

Find OP
2OP =OO'

use pythagorean theorem to find the length of hypotenuse OP of triangle ODP

O'P =13cm

OO' = 26cm=AB

right you are!

:) WELL DONE

yw :)

yw.