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zurf
Group Title
Two capacitors, one 7.0 microfarad & the other 15 microfarad , are connected in series across a 15 V battery. Find the charge stored on each capacitors.
 one year ago
 one year ago
zurf Group Title
Two capacitors, one 7.0 microfarad & the other 15 microfarad , are connected in series across a 15 V battery. Find the charge stored on each capacitors.
 one year ago
 one year ago

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Mashy Group TitleBest ResponseYou've already chosen the best response.0
Well i do hope you know that when capacitors are connected in series, they store exactly the same amount of charge.. i can prove it.. but.. the proof must be available in your textbook :P.. so anyways.. find out the equivalent capacitance.. nd 15V comes across this equivalent capacitance, and now using the basic capacitor formula, calculate the charge stored by it..
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
The joint capacitance = product * sum = (7 * 15)(7 + 15) = 4.773 microfarads. Q = CV = 4.773 * 15 microcoulombs. This is the charge stored on each capacitor.
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
You're welcome :)
 one year ago
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