A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Two capacitors, one 7.0 microfarad & the other 15 microfarad , are connected in series across a 15 V battery. Find the charge stored on each capacitors.
anonymous
 3 years ago
Two capacitors, one 7.0 microfarad & the other 15 microfarad , are connected in series across a 15 V battery. Find the charge stored on each capacitors.

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well i do hope you know that when capacitors are connected in series, they store exactly the same amount of charge.. i can prove it.. but.. the proof must be available in your textbook :P.. so anyways.. find out the equivalent capacitance.. nd 15V comes across this equivalent capacitance, and now using the basic capacitor formula, calculate the charge stored by it..

kropot72
 3 years ago
Best ResponseYou've already chosen the best response.0The joint capacitance = product * sum = (7 * 15)(7 + 15) = 4.773 microfarads. Q = CV = 4.773 * 15 microcoulombs. This is the charge stored on each capacitor.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.