## starrlight 2 years ago 11* 3 sqrt 6+8* 4 sqrt 6 +2* 3sqrt 6-3* 4sqrt 6

1. hba

$\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile$

2. starrlight

hi

3. hba

$11*3\sqrt{6}+8*4\sqrt{6}+2*3\sqrt{6}-3*4\sqrt{6},Right ?$

4. starrlight

A) 18 sqrt 12 B) 18 sqrt 6 C) 5 4 sqrt 12+13 3 sqrt 12 D

5. starrlight

D) 5 4 sqrt 6+133 sqrt 6

6. hba

Can you simplify it ?

7. starrlight

im not sure what im doing with this problem it is asking me to simplify

8. hba

We just have to simply add them up but before we do this we have to multiply the terms Example 2*3sqrt{6}=6sqrt{6}

9. starrlight

when i simplified it i got 59 sqrt 6 but thats not one of the options

10. hba

Show me you working :)

11. starrlight

let me try it your way so 11 3 sqrt 6 is ....33 sqrt 6 i think

12. hba

Yeah good :)

13. hba

Now do the others and then add,subtract them :)

14. starrlight

ok

15. starrlight

33 sqrt 6+32 sqrt 6+6 sqrt 6-12 sqrt 6

16. starrlight

it still comes out to 59 sqrt 6

17. hba

Is your question correct my friend ?

18. hba

lol :P

19. starrlight

ya i think so its just im taking this class on flvs and they always have the wierdest answer ... like you solve the problem and then its wrong and apparently their answer is right

20. hba

Haha lol :P

21. starrlight

hold on the question itself is a picture ill attach it

22. starrlight

23. hba

lol,the question is diffrent lemme show you this.

24. hba

You will add these $\huge\ a \sqrt[3]{6}+b \sqrt[3]{6}=(a+b)\sqrt[3]{6}$ You add this and also add the other.

25. starrlight

i dont understand that

26. hba

@starrlight $\huge\ 11\sqrt[3]{6}+8\sqrt[4]{6}+2\sqrt[3]{6}-3\sqrt[4]{6}$ Add them straight up :)

27. hba

@starrlight Um,getting it ?

28. starrlight

no

29. hba

$\huge\ 11\sqrt[3]{6}+2\sqrt[3]{6}+8\sqrt[4]{6}-3\sqrt[4]{6}$

30. starrlight

oh ok