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johnnyalln

  • 3 years ago

Simplify the expression: \[(\tan \Theta+1)(\tan \Theta-1)\]

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  1. zepdrix
    • 3 years ago
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    See how each set of brackets contains the same thing except with a sign change? These are CONJUGATES. When you multiply conjugates you get the difference of squares. Example:\[\large (x-y)(x+y)=x^2-y^2\]

  2. syhna
    • 3 years ago
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    cot^2 thaeta?

  3. johnnyalln
    • 3 years ago
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    what about \[\tan^{2} \Theta-1\]

  4. zepdrix
    • 3 years ago
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    Yup looks good! c: And since we don't have an identity for tan^2 - 1, it looks like that's as far as we can simplify it.

  5. johnnyalln
    • 3 years ago
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    got it. thanks!

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