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brookester6
 2 years ago
Use substitution to solve the problem...
x=9y
x+4=5(y+4)
I already now that you can plug x in to the second equation and then distribute but what next?
brookester6
 2 years ago
Use substitution to solve the problem... x=9y x+4=5(y+4) I already now that you can plug x in to the second equation and then distribute but what next?

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zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1\[\large \color{orangered}{x=9y}\]\[\large \color{orangered}{x}+4=5(y+4) \qquad \rightarrow \qquad \color{orangered}{9y}+4=5(y+4)\]Distributing gives us,\[\large 9y+4=5y+20\]So you've gotten this much done so far? Hmm ok. Subtract 5y from each side,\[9y5y+4=\cancel{5y5y}+20\]

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1\[\large 4y+4=20\]Subtract 4 from each side,\[4y+\cancel{44}=204\]

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Understand the process of combining like terms? :D That's how the 9y and 5y combined.

mathstudent55
 2 years ago
Best ResponseYou've already chosen the best response.0You already have the first equation solved for x. So plug in what x is equal to, 9y, into the second equation and solve for y.

brookester6
 2 years ago
Best ResponseYou've already chosen the best response.0yea, now y = 4 and i plug it in to the top equation :) Thanks so much!!
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