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brookester6
Group Title
Use substitution to solve the problem...
x=9y
x+4=5(y+4)
I already now that you can plug x in to the second equation and then distribute but what next?
 one year ago
 one year ago
brookester6 Group Title
Use substitution to solve the problem... x=9y x+4=5(y+4) I already now that you can plug x in to the second equation and then distribute but what next?
 one year ago
 one year ago

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zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large \color{orangered}{x=9y}\]\[\large \color{orangered}{x}+4=5(y+4) \qquad \rightarrow \qquad \color{orangered}{9y}+4=5(y+4)\]Distributing gives us,\[\large 9y+4=5y+20\]So you've gotten this much done so far? Hmm ok. Subtract 5y from each side,\[9y5y+4=\cancel{5y5y}+20\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large 4y+4=20\]Subtract 4 from each side,\[4y+\cancel{44}=204\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Understand the process of combining like terms? :D That's how the 9y and 5y combined.
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.0
You already have the first equation solved for x. So plug in what x is equal to, 9y, into the second equation and solve for y.
 one year ago

brookester6 Group TitleBest ResponseYou've already chosen the best response.0
yea, now y = 4 and i plug it in to the top equation :) Thanks so much!!
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
yay good job c:
 one year ago
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