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so this is really
\[\frac{(2x^2 + 17x + 35)}{(x + 5)}\]
can you factor the numerator..?

No, there is no GCF.

yes there is... do you know how to factorise a quadratic..?

no

I have a better idea for you,
Use Synthetic division method.

the factors of this are of the form
(2x + a )(x + b)
where a * b = 35 and 2a + b = 17

why not just factorise
\[\frac{(x + 5)(2x + 7)}{(x + 5)}\]

sorry 2b + a = 17

yes - its easier to just factorise if you are competent at this

so then the (x + 5) in the denominator cancels out the (x + 5) in the numerator, leaving (2x + 7)?

right

thats correct... easy if you can factor..

Okay, thanks!