DeadShot
Divide 2x^2 + 17x + 35 by x + 5.
A. x + 7
B. 2x + 7
C. x + 27
D. 2x + 27



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campbell_st
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so this is really
\[\frac{(2x^2 + 17x + 35)}{(x + 5)}\]
can you factor the numerator..?

DeadShot
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No, there is no GCF.

campbell_st
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yes there is... do you know how to factorise a quadratic..?

DeadShot
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no

hba
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I have a better idea for you,
Use Synthetic division method.

cwrw238
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the factors of this are of the form
(2x + a )(x + b)
where a * b = 35 and 2a + b = 17

campbell_st
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why not just factorise
\[\frac{(x + 5)(2x + 7)}{(x + 5)}\]

cwrw238
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sorry 2b + a = 17

cwrw238
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yes  its easier to just factorise if you are competent at this

DeadShot
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so then the (x + 5) in the denominator cancels out the (x + 5) in the numerator, leaving (2x + 7)?

cwrw238
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right

campbell_st
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thats correct... easy if you can factor..

DeadShot
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Okay, thanks!