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DeadShot
 3 years ago
Divide 2x^2 + 17x + 35 by x + 5.
A. x + 7
B. 2x + 7
C. x + 27
D. 2x + 27
DeadShot
 3 years ago
Divide 2x^2 + 17x + 35 by x + 5. A. x + 7 B. 2x + 7 C. x + 27 D. 2x + 27

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campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1so this is really \[\frac{(2x^2 + 17x + 35)}{(x + 5)}\] can you factor the numerator..?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1yes there is... do you know how to factorise a quadratic..?

hba
 3 years ago
Best ResponseYou've already chosen the best response.0I have a better idea for you, Use Synthetic division method.

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0the factors of this are of the form (2x + a )(x + b) where a * b = 35 and 2a + b = 17

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1why not just factorise \[\frac{(x + 5)(2x + 7)}{(x + 5)}\]

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0yes  its easier to just factorise if you are competent at this

DeadShot
 3 years ago
Best ResponseYou've already chosen the best response.0so then the (x + 5) in the denominator cancels out the (x + 5) in the numerator, leaving (2x + 7)?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1thats correct... easy if you can factor..
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