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DeadShot

  • 3 years ago

Divide 2x^2 + 17x + 35 by x + 5. A. x + 7 B. 2x + 7 C. x + 27 D. 2x + 27

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  1. campbell_st
    • 3 years ago
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    so this is really \[\frac{(2x^2 + 17x + 35)}{(x + 5)}\] can you factor the numerator..?

  2. DeadShot
    • 3 years ago
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    No, there is no GCF.

  3. campbell_st
    • 3 years ago
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    yes there is... do you know how to factorise a quadratic..?

  4. DeadShot
    • 3 years ago
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    no

  5. hba
    • 3 years ago
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    I have a better idea for you, Use Synthetic division method.

  6. cwrw238
    • 3 years ago
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    the factors of this are of the form (2x + a )(x + b) where a * b = 35 and 2a + b = 17

  7. campbell_st
    • 3 years ago
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    why not just factorise \[\frac{(x + 5)(2x + 7)}{(x + 5)}\]

  8. cwrw238
    • 3 years ago
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    sorry 2b + a = 17

  9. cwrw238
    • 3 years ago
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    yes - its easier to just factorise if you are competent at this

  10. DeadShot
    • 3 years ago
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    so then the (x + 5) in the denominator cancels out the (x + 5) in the numerator, leaving (2x + 7)?

  11. cwrw238
    • 3 years ago
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    right

  12. campbell_st
    • 3 years ago
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    thats correct... easy if you can factor..

  13. DeadShot
    • 3 years ago
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    Okay, thanks!

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