## anonymous 3 years ago Divide 2x^2 + 17x + 35 by x + 5. A. x + 7 B. 2x + 7 C. x + 27 D. 2x + 27

1. campbell_st

so this is really $\frac{(2x^2 + 17x + 35)}{(x + 5)}$ can you factor the numerator..?

2. anonymous

No, there is no GCF.

3. campbell_st

yes there is... do you know how to factorise a quadratic..?

4. anonymous

no

5. hba

I have a better idea for you, Use Synthetic division method.

6. cwrw238

the factors of this are of the form (2x + a )(x + b) where a * b = 35 and 2a + b = 17

7. campbell_st

why not just factorise $\frac{(x + 5)(2x + 7)}{(x + 5)}$

8. cwrw238

sorry 2b + a = 17

9. cwrw238

yes - its easier to just factorise if you are competent at this

10. anonymous

so then the (x + 5) in the denominator cancels out the (x + 5) in the numerator, leaving (2x + 7)?

11. cwrw238

right

12. campbell_st

thats correct... easy if you can factor..

13. anonymous

Okay, thanks!