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DeadShot
Group Title
Divide 2x^2 + 17x + 35 by x + 5.
A. x + 7
B. 2x + 7
C. x + 27
D. 2x + 27
 one year ago
 one year ago
DeadShot Group Title
Divide 2x^2 + 17x + 35 by x + 5. A. x + 7 B. 2x + 7 C. x + 27 D. 2x + 27
 one year ago
 one year ago

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campbell_st Group TitleBest ResponseYou've already chosen the best response.1
so this is really \[\frac{(2x^2 + 17x + 35)}{(x + 5)}\] can you factor the numerator..?
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
No, there is no GCF.
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
yes there is... do you know how to factorise a quadratic..?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
I have a better idea for you, Use Synthetic division method.
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
the factors of this are of the form (2x + a )(x + b) where a * b = 35 and 2a + b = 17
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
why not just factorise \[\frac{(x + 5)(2x + 7)}{(x + 5)}\]
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
sorry 2b + a = 17
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
yes  its easier to just factorise if you are competent at this
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
so then the (x + 5) in the denominator cancels out the (x + 5) in the numerator, leaving (2x + 7)?
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
thats correct... easy if you can factor..
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
Okay, thanks!
 one year ago
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