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Divide 2x^2 + 17x + 35 by x + 5. A. x + 7 B. 2x + 7 C. x + 27 D. 2x + 27

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so this is really \[\frac{(2x^2 + 17x + 35)}{(x + 5)}\] can you factor the numerator..?
No, there is no GCF.
yes there is... do you know how to factorise a quadratic..?

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Other answers:

  • hba
I have a better idea for you, Use Synthetic division method.
the factors of this are of the form (2x + a )(x + b) where a * b = 35 and 2a + b = 17
why not just factorise \[\frac{(x + 5)(2x + 7)}{(x + 5)}\]
sorry 2b + a = 17
yes - its easier to just factorise if you are competent at this
so then the (x + 5) in the denominator cancels out the (x + 5) in the numerator, leaving (2x + 7)?
thats correct... easy if you can factor..
Okay, thanks!

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