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SForce

  • 3 years ago

Simplify (4y^2-13y+3)/(2y^2-5y-12)(2y^2+9y+9)/(16y^2-1)(y^2+3y-28)/(y^2-9)

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  1. campbell_st
    • 3 years ago
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    well start by factorising the quadratics which will give \[\frac{(4y -1)(y -3)}{(2y + 3)( y - 4)} \times \frac{(2y + 3)(y + 3)}{(4y -1)(4y + 1)} \times \frac{(y + 7)(y - 3)}{(y - 3)(y+3)}\] now just cancel common factors... the distribute to get the final simplification.

  2. Azteck
    • 3 years ago
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    Incorrect @campbell_st \[\frac{ (4y-1)(y-3) }{ (2y+3)(y-4) }\times \frac{ (2y+3)(y+3) }{ (4y-1)(4y+1) }\times \frac{ (y+7)(y-4) }{ (y-3)(y+3) }\]

  3. Azteck
    • 3 years ago
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    You incorrectly factorised the numerator of the last fraction.

  4. Azteck
    • 3 years ago
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    \[=y+7\]

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