anonymous
  • anonymous
Simplify (4y^2-13y+3)/(2y^2-5y-12)(2y^2+9y+9)/(16y^2-1)(y^2+3y-28)/(y^2-9)
Pre-Algebra
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

campbell_st
  • campbell_st
well start by factorising the quadratics which will give \[\frac{(4y -1)(y -3)}{(2y + 3)( y - 4)} \times \frac{(2y + 3)(y + 3)}{(4y -1)(4y + 1)} \times \frac{(y + 7)(y - 3)}{(y - 3)(y+3)}\] now just cancel common factors... the distribute to get the final simplification.
anonymous
  • anonymous
Incorrect @campbell_st \[\frac{ (4y-1)(y-3) }{ (2y+3)(y-4) }\times \frac{ (2y+3)(y+3) }{ (4y-1)(4y+1) }\times \frac{ (y+7)(y-4) }{ (y-3)(y+3) }\]
anonymous
  • anonymous
You incorrectly factorised the numerator of the last fraction.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[=y+7\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.