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michelle95
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find teh gcf and factor the expression. problem in comments. best answer and i will become a fan
 one year ago
 one year ago
michelle95 Group Title
find teh gcf and factor the expression. problem in comments. best answer and i will become a fan
 one year ago
 one year ago

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michelle95 Group TitleBest ResponseYou've already chosen the best response.0
\[4n^{2}20n+24\]
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
The greatest common factor is the factor that is the largest present among all of your numbers. So: 4 has factors: 1, 2, 4 20 has factors: 1, 2, 4, 5, 10, 20 24 has factors: 1, 2, 3, 4, 6, 8, 12, 24 Which number is largest among all of them? 4 is! So you factor our the 4 from your expression. When you do you, you are essentially dividing out each term by 4 in the parentheses: \[4n^220n+24=4(n^25n+6)\]
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
Now, in order to factor it out even more, there is a way to do this: You find two numbers (say you call them a and b) such that a*b=6 (the middle number), and a+b=5 (the last number). You can think of a=2 and b=3 (Why? because a*b = (2)*(3)=6 and a+b=(2)+(3)=5) So once you have these 2 numbers a,b, you write down your factors as: (n+a)(n+b). This will the general form to write out your factors. Then just substitute the values of a and b: (n+(2))(n+(3)) = (n2)(n3) Now you had a 4 initially before the parentheses: so you get 4(n2)(n3)
 one year ago

kirbykirby Group TitleBest ResponseYou've already chosen the best response.1
You can always double check your by multiplying out your factors: 4(n2)(n3) = 4[n^23n2n+6] = 4[n^25n+6]=4n^220n+24
 one year ago
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