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6532bunny
Group Title
Verify the identity.
sin (4u) = 2 sin (2u) cos (2u)
Please help, verifying these kind of equations is tricky for me.
 one year ago
 one year ago
6532bunny Group Title
Verify the identity. sin (4u) = 2 sin (2u) cos (2u) Please help, verifying these kind of equations is tricky for me.
 one year ago
 one year ago

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slaaibak Group TitleBest ResponseYou've already chosen the best response.1
Hmm. you can try doing it like this: sin(2u + 2u) = sin(2u) * cos(2u) + cos(2u) * sin(2u) = 2sin(2u)*cos(2u) Note: I referred to: sin(A + B) = sinAcosB + cosAsinB
 one year ago

6532bunny Group TitleBest ResponseYou've already chosen the best response.0
Oh, I see. Is that the final answer?
 one year ago

6532bunny Group TitleBest ResponseYou've already chosen the best response.0
I mean, is that it? Usually these questions take up more space. >_<
 one year ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.1
I'm pretty sure it is, yes
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
you can also use the identity that \[\bf \large \boxed{\sin 2A= 2\sin A \times \cos A }\]
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
treating \[4u=2 \times (2u) \]
 one year ago
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