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Question in comments...plz help

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i really need an explanation or showing of work.

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Other answers:

Holy chiznets. What type of math is this. Geometry, Triginometry, Calculus, Algebra, etc.
1 or 2
quadratic inequalities
Can't help you their. I'm just getting out of Geometry. I take Algebra II starting Tuesday. Sorry laddy.
it's okay, thanks for trying
I aced Algebra I though I know that much. In my day we didn't have all this fancy schmancy stuff(I'm only 14). I don't know nuttn bout dis der Aljero!
I gotta kick outta that
im 14 also...
i need to find the solution set of the inequality.
Will you give me a medal for trying?? :DD
Can you please solve the quadratic equation first? I mean to find that value of a when the equation is 0
ya im pretty sure it's \[a^2-5a-2a+10\] After it's been factored it's \[(a-5)(a-2)(a-5)(a-2)\]
Not quite..
No repeated factors in this case.
so just \[(a−5)(a−2)\] ?
There are four factors :)
so \[(a−5)(a−2)(a+5)(a+2)\] ?
|dw:1358566081932:dw| So, the graph is like this (sorry for my poor drawing..) In what region does the function have a value less than 0?
i think i got it from here. one more thing does \[(a^2-5a-2a+10)^2\] become \[(a^2-7a+10)(a^2-7a+10)\]?
Are you still working on the factorization part?
ya im making sure how i got the wrong answer.
i think i messed up in the factorization
\[a^4 - 29a^2 +100\]\[=a^4 - 25a^2 - 4a^2 +100\]\[=a^2 (a^2-25) -4(a^2 - 25)\]\[=(a^2-4)(a^2-25)\]\[=(a-2)(a+2)(a^2-25)\]\[=(a-2)(a+2)(a-5)(a+5)\] The last two steps are just using the identity of difference of two squares. \(a^2-b^2 = (a+b)(a-b)\)
I don't know how you get this: \[(a^2-5a-2a+10)^2\]
Thanks so much for this. :D
You're welcome :)

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