Question in comments...plz help

- anonymous

Question in comments...plz help

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

Ok.

- anonymous

\[a^4-29a^2+100<0\]

- anonymous

i really need an explanation or showing of work.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Holy chiznets. What type of math is this. Geometry, Triginometry, Calculus, Algebra, etc.

- anonymous

Algebra

- anonymous

1 or 2

- anonymous

2

- anonymous

quadratic inequalities

- anonymous

Can't help you their. I'm just getting out of Geometry. I take Algebra II starting Tuesday. Sorry laddy.

- anonymous

it's okay, thanks for trying

- anonymous

I aced Algebra I though I know that much. In my day we didn't have all this fancy schmancy stuff(I'm only 14). I don't know nuttn bout dis der Aljero!

- anonymous

I gotta kick outta that

- anonymous

im 14 also...

- anonymous

i need to find the solution set of the inequality.

- anonymous

Will you give me a medal for trying?? :DD

- anonymous

Maybe...

- anonymous

Can you please solve the quadratic equation first?
I mean to find that value of a when the equation is 0

- anonymous

Tehehe.

- anonymous

ya im pretty sure it's \[a^2-5a-2a+10\]
After it's been factored it's \[(a-5)(a-2)(a-5)(a-2)\]

- anonymous

Not quite..

- anonymous

No repeated factors in this case.

- anonymous

so just \[(a−5)(a−2)\] ?

- anonymous

There are four factors :)

- anonymous

so \[(a−5)(a−2)(a+5)(a+2)\] ?

- anonymous

Bingo!

- anonymous

|dw:1358566081932:dw|
So, the graph is like this (sorry for my poor drawing..)
In what region does the function have a value less than 0?

- anonymous

*regions

- anonymous

i think i got it from here. one more thing does \[(a^2-5a-2a+10)^2\]
become \[(a^2-7a+10)(a^2-7a+10)\]?

- anonymous

Are you still working on the factorization part?

- anonymous

ya im making sure how i got the wrong answer.

- anonymous

i think i messed up in the factorization

- anonymous

\[a^4 - 29a^2 +100\]\[=a^4 - 25a^2 - 4a^2 +100\]\[=a^2 (a^2-25) -4(a^2 - 25)\]\[=(a^2-4)(a^2-25)\]\[=(a-2)(a+2)(a^2-25)\]\[=(a-2)(a+2)(a-5)(a+5)\]
The last two steps are just using the identity of difference of two squares.
\(a^2-b^2 = (a+b)(a-b)\)

- anonymous

I don't know how you get this:
\[(a^2-5a-2a+10)^2\]

- anonymous

Thanks so much for this. :D

- anonymous

You're welcome :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.