Question in comments...plz help

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Question in comments...plz help

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Ok.
\[a^4-29a^2+100<0\]
i really need an explanation or showing of work.

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Other answers:

Holy chiznets. What type of math is this. Geometry, Triginometry, Calculus, Algebra, etc.
Algebra
1 or 2
2
quadratic inequalities
Can't help you their. I'm just getting out of Geometry. I take Algebra II starting Tuesday. Sorry laddy.
it's okay, thanks for trying
I aced Algebra I though I know that much. In my day we didn't have all this fancy schmancy stuff(I'm only 14). I don't know nuttn bout dis der Aljero!
I gotta kick outta that
im 14 also...
i need to find the solution set of the inequality.
Will you give me a medal for trying?? :DD
Maybe...
Can you please solve the quadratic equation first? I mean to find that value of a when the equation is 0
Tehehe.
ya im pretty sure it's \[a^2-5a-2a+10\] After it's been factored it's \[(a-5)(a-2)(a-5)(a-2)\]
Not quite..
No repeated factors in this case.
so just \[(a−5)(a−2)\] ?
There are four factors :)
so \[(a−5)(a−2)(a+5)(a+2)\] ?
Bingo!
|dw:1358566081932:dw| So, the graph is like this (sorry for my poor drawing..) In what region does the function have a value less than 0?
*regions
i think i got it from here. one more thing does \[(a^2-5a-2a+10)^2\] become \[(a^2-7a+10)(a^2-7a+10)\]?
Are you still working on the factorization part?
ya im making sure how i got the wrong answer.
i think i messed up in the factorization
\[a^4 - 29a^2 +100\]\[=a^4 - 25a^2 - 4a^2 +100\]\[=a^2 (a^2-25) -4(a^2 - 25)\]\[=(a^2-4)(a^2-25)\]\[=(a-2)(a+2)(a^2-25)\]\[=(a-2)(a+2)(a-5)(a+5)\] The last two steps are just using the identity of difference of two squares. \(a^2-b^2 = (a+b)(a-b)\)
I don't know how you get this: \[(a^2-5a-2a+10)^2\]
Thanks so much for this. :D
You're welcome :)

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