A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
I wrote it in MIT's 8.01[OCW  Physics] subject, but seems that there are not much movement..
At the end of lecture 12, Prof. Walter Lewin asks if the time for an object that is launched from ground zero with an angle != 0 to reach the maximun altitude (point P) is the same as it to land from there to y=0. Considering air drag.
Shall we discuss it?
anonymous
 3 years ago
I wrote it in MIT's 8.01[OCW  Physics] subject, but seems that there are not much movement.. At the end of lecture 12, Prof. Walter Lewin asks if the time for an object that is launched from ground zero with an angle != 0 to reach the maximun altitude (point P) is the same as it to land from there to y=0. Considering air drag. Shall we discuss it?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0At the highest point of altitude what is your velocity?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Velocity in the y direction that is

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and think about what variable are in air drag

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think considering that the drag constant b doesn't change !

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.youtube.com/watch?v=9lvNofoUYwI&list=PLF688ECB2FF119649 This is the lecture. The problem is given at the last seconds. Sure the velocity is zero at the highest point, and since we can disconsider the velocity in x axis (?), the only thing that is to be analized is the motion in y axis. I am to say yes, both times are the same, but i wouldn't be surprised if considering drag force could change the asnwer. The viscosity/pressure regime's influency in the motion is quite confuse for me to understand. Moreover, the considered object is a sphere (for simplicity), and just to say, the whole question may have been caused because i'm not so good in english haha. http://ocw.mit.edu//courses/physics/801physicsiclassicalmechanicsfall1999/lecturenotes/sup5_1.pdf

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0As the object moves up both g and air drag act downward and hence the retardation is "more" than g. When it comes down g is downwards but air drag is upwards. Hence acceleration is "less" than g. Since vertical distance to be covered is same in both the cases, it will take more time to come down than to go up.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.