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jayshane

  • one year ago

xcos y-y =cosxy by implicit differentiation pls help!!

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  1. AravindG
    • one year ago
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    ok tell me where are you stuck in doing this question?

  2. jayshane
    • one year ago
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    i dont have no idea in solving that...its our assignment and it was not been discussed

  3. AravindG
    • one year ago
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    ok i suggest you differentiate both sides and bring y' to one side

  4. Callisto
    • one year ago
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    @jayshane We have to differentiate both sides. Hmm... shall we differentiate term by term? I think it would be easier for you to understand..

  5. AravindG
    • one year ago
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    keep in mind \[\large \bf \text{differential of sum =sum of differentials }\]

  6. jayshane
    • one year ago
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    example equation pls!!!

  7. Callisto
    • one year ago
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    Example: Differentiate a sinb with respect to a \[\frac{d}{da}asinb=sinb\frac{d}{da}a + a\frac{d}{da}sinb =sinb + a(cosb)(b')\]

  8. jayshane
    • one year ago
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    -sin xyy`=-sin xyy` ?

  9. Callisto
    • one year ago
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    For cosxy \[\frac{d}{dx}cos(xy) = \frac{d}{du}cos(u) \times \frac{d}{dx}(xy)\]u= xy\[=-sinu \times (y\frac{d}{dx}x +x\frac{d}{dx}x)\]\[=...\]

  10. AravindG
    • one year ago
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    .......

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